Answer:
here north are not vector option b hope ur help
Answer:
The induced emf in the loop is 
Explanation:
Given that,
Length of the wire, L = 1.22 m
It changes its shape is changed from square to circular. Then the side of square be its circumference, 4a = L
4a = 1.22
a = 0.305 m
Area of square, 
Circumference of the loop,
Area of circle,
The induced emf is given by :
So, the induced emf in the loop is
Answer:
v = -v₀ / 2
Explanation:
For this exercise let's use kinematics relations.
Let's use the initial conditions to find the acceleration of the electron
v² = v₀² - 2a y
when the initial velocity is vo it reaches just the negative plate so v = 0
a = v₀² / 2y
now they tell us that the initial velocity is half
v’² = v₀’² - 2 a y’
v₀ ’= v₀ / 2
at the point where turn v = 0
0 = v₀² /4 - 2 a y '
v₀² /4 = 2 (v₀² / 2y) y’
y = 4 y'
y ’= y / 4
We can see that when the velocity is half, advance only ¼ of the distance between the plates, now let's calculate the velocity if it leaves this position with zero velocity.
v² = v₀² -2a y’
v² = 0 - 2 (v₀² / 2y) y / 4
v² = -v₀² / 4
v = -v₀ / 2
We can see that as the system has no friction, the arrival speed is the same as the exit speed, but with the opposite direction.
Answer:
D. gravitational potential energy
Explanation:
