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topjm [15]
3 years ago
7

At the end of an amusement park ride, it is desirable to bring a gondola to a stop without having the acceleration exceed 3 g. I

f the total mass of the gondola and its occupants is 1,727 kg, what is the maximum allowed braking force
Physics
1 answer:
notsponge [240]3 years ago
6 0

The break force of the gondola in the amusement park ride is 50,773.8 N.

<h3>Break force of the gondola</h3>

The break force of the gondola in the amusement park ride, is calculated by applying Newton's second law of motion as shown below;

F = ma

where;

  • m is the total mass = 1,727 kg
  • a is acceleration = 3g = 3 x 9.8 m/s² = 29.4 m/s²

F = 1,727 x 29.4

F = 50,773.8 N

Thus, the break force of the gondola in the amusement park ride is 50,773.8 N.

Learn more about breaking force here: brainly.com/question/7434235

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8 0
3 years ago
A closely wound search coil has an area of 3.21 cm2, 120 turns, and a resistance of 58.7 O. It is connected to a charge-measurin
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Answer:

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Explanation:

To solve the exercise it is necessary to use the concepts related to Faraday's Law, magnetic flux and ohm's law.

By Faraday's law we know that

\epsilon = \frac{NBA}{t}

Where,

\epsilon  =electromotive force

N = Number of loops

B = Magnetic field

A = Area

t= Time

For Ohm's law we now that,

V = IR

Where,

I = Current

R = Resistance

V = Voltage (Same that the electromotive force at this case)

In this system we have that the resistance in series of coil and charge measuring device is given by,

R = R_c + R_d

And that the current can be expressed as function of charge and time, then

I = \frac{q}{t}

Equation Faraday's law and Ohm's law we have,

V = \epsilon

IR = \frac{NBA}{t}

(\frac{q}{t})(R_c+R_d) = \frac{NBA}{t}

Re-arrange for Magnetic Field B, we have

B = \frac{q(R_c+R_d)}{NA}

Our values are given as,

R_c = 58.7\Omega

R_d = 45.5\Omega

N = 120

q = 3.53*10^{-5}C

A = 3.21cm^2 = 3.21*10^{-4}m^2

Replacing,

B = \frac{(3.53*10^{-5})(58.7+45.5)}{120*3.21*10^{-4}}

B = 0.095T

Therefore the magnetic field in the System is 0.095T

3 0
3 years ago
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