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topjm [15]
3 years ago
7

At the end of an amusement park ride, it is desirable to bring a gondola to a stop without having the acceleration exceed 3 g. I

f the total mass of the gondola and its occupants is 1,727 kg, what is the maximum allowed braking force
Physics
1 answer:
notsponge [240]3 years ago
6 0

The break force of the gondola in the amusement park ride is 50,773.8 N.

<h3>Break force of the gondola</h3>

The break force of the gondola in the amusement park ride, is calculated by applying Newton's second law of motion as shown below;

F = ma

where;

  • m is the total mass = 1,727 kg
  • a is acceleration = 3g = 3 x 9.8 m/s² = 29.4 m/s²

F = 1,727 x 29.4

F = 50,773.8 N

Thus, the break force of the gondola in the amusement park ride is 50,773.8 N.

Learn more about breaking force here: brainly.com/question/7434235

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