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zubka84 [21]
3 years ago
8

Number of moles in 1.806*10^22 molecules of nitrogen

Chemistry
1 answer:
Fynjy0 [20]3 years ago
3 0
Hi there!

• Avogadro's number = 6.023 × 10²³
• No.of molecules in N = 1.806 × 10²²  [ Given ]

It's known that :-

Number of molecules = Moles × Avogadro's number

=> 1.806 × 10²² = Mol. × 6.023 × 10²³

=> Mole = \dfrac {1.806 \cdot 10^{22} }{6.023 \cdot 10^{23} }

=> Moles = 0.03 mol.

Hence, 0.03 mol. is th' required answer.

~ Hope it helps!
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How many molecules of CBr4 are in 250 grams of CBr4
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Answer:- 4.54*10^2^3 molecules.

Solution:- The grams of tetrabromomethane are given and it asks to calculate the number of molecules.

It is a two step unit conversion problem. In the first step, grams are converted to moles on dividing the grams by molar mass.

In second step, the moles are converted to molecules on multiplying by Avogadro number.

Molar mass of CBr_4  = 12+4(79.9)  = 331.6 g per mol

let's make the set up using dimensional analysis:

250g(\frac{1mol}{331.6g})(\frac{6.022*10^2^3molecules}{1mol})

= 4.54*10^2^3 molecules

So, there will be 4.54*10^2^3 molecules in 250 grams of CBr_4 .


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