Answer:
x = ±3 sqrt(2)
Step-by-step explanation:
x^2 + x^2=6^2
Combine like terms
2x^2 = 6^2
Divide each side by 2
x^2 = * 6^2/2
Take the square root of each side
sqrt(x^2) =± sqrt( 6^2/2)
Remember that sqrt(a/b) = ±sqrt(a ) /sqrt(b)
x = ±sqrt(6^2)/sqrt(2)
x = ±6 /sqrt(2)
We do not leave square roots in the denominator, so we multiply the top and bottom by sqrt(2)
x = ±6 /sqrt(2) * sqrt(2)/ sqrt(2)
x = ±6 *sqrt(2) /( sqrt(2)*sqrt(2))
x = ±6 sqrt(2) /(2)
x = ±3 sqrt(2)
Answer:
Pythagorean’s theorem states that if a^2 + b^2 = c^2 where c is the hypotenuse and a and b are the side lengths of the right triangle
Given that we can plug in
a= 6 , b = 8 , c = 10
We get an equation:
6^2 + 8^2 = 10^2
36 + 64 = 100
100 = 100
- Answer & step-by-step explanation:
<em>a) impossible</em>
<em>b) the sum of the angles in a triangle is 180°</em>
<em>63° + 59° + 57° = 179°</em>
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