Assuming the order required is as n-> inf.
As n->inf, o(log(n+1)) -> o(log(n)) since the 1 is insignificant compared with n.
We can similarly drop the "1" as n-> inf, the expression becomes log(n^2+1) ->
log(n^2)=2log(n) which is still o(log(n)).
So yes, both are o(log(n)).
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<span>How many 1/100 are in 3/10
multiply by 10 for both numerator and denominator
3/10 = 30/100
Ans: 30
So that there are 30 1/100 in 3/10</span>
Answer:
I would say B) approx. 35
Step-by-step explanation:
Because that is so close to 45 degrees which is closest to 35
Answer:
18150
Step-by-step explanation:
330*55=18150
Either a = - 2/T or a = t + 2
