Note:
Do the square first, and then you do mathematic operation between the parentheses. And, then do the
mathematic operation in the outside of parentheses.
Thank you.
Answer:
72 sq. mi
Step-by-step explanation:
Breaking this down, we have 2 right triangles with sides of 3, 4, and 5 miles, and 3 rectangles with dimensions 3 x 5, 4 x 5, and 5 x 5 miles. Remember that the area of a triangle is 1/2 x b x h , where b and h are the triangle's base and height. The base and height of the triangles at the bases of the figure are 3 and 4, so each triangle has an area of 1/2 x 3 x 4 = 1/2 x 12 = 6 sq. mi, or 6 + 6 = 12 sq. mi together.
Onto the rectangles, we can find their area by multiplying their length by their width. Since the width of these rectangles is the same for all three - 5 mi - we can make our lives a little easier and just "glue" the lengths together, giving us a longer rectangle with a length of 3 + 4 + 5 = 12 mi. Multiplying the two, we find the area of the rectangles to be 5 x 12 = 60 sq. mi.
Adding this area to the triangle's area gives us a total area of 12 + 60 = 72 sq. mi.
Answer: Choice C
Vertex = (5, -2)
===============================================
Explanation:
Vertex form is 
where the vertex itself is located at (h,k)
As the name implies, we can very quickly pull out the coordinates of the vertex without doing much math at all.
In the case of choice C, we have 
which is the same as 
and we can see that h = 5 and k = -2. Therefore, the vertex is located at (h,k) = (5, -2)
Answer:
The number of people needed is 
Step-by-step explanation:
From the question we are told that
The population proportion is 
The margin of error is 
From the question we are told the confidence level is 90% , hence the level of significance is
=> 
Generally from the normal distribution table the critical value of 
is
Generally the sample size is mathematically represented as
![n =[ \frac{Z_{\frac{\alpha }{2} }}{E} ]^2 * p(1-p)](https://tex.z-dn.net/?f=n%20%3D%5B%20%5Cfrac%7BZ_%7B%5Cfrac%7B%5Calpha%20%7D%7B2%7D%20%7D%7D%7BE%7D%20%5D%5E2%20%2A%20p%281-p%29)
=> ![n =[ \frac{1.645 }{0.03} ]^2 * 0.65(1-0.65)](https://tex.z-dn.net/?f=n%20%3D%5B%20%5Cfrac%7B1.645%20%7D%7B0.03%7D%20%5D%5E2%20%2A%200.65%281-0.65%29)
=>
Answer: Thanks! It's alright!
