Help me please it’s not a or b btw
2 answers:
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We have the cards numbered as 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, and 12.
Sample number is, n(S)=11.
We pick a card and want to get even number like 2, 4, 6, 8, 10, and 12.
Probability of picking an even number would be :-
P(even numbers) =
Now we replace the card and want to get a 7 in second attempt.
Probability of picking a 7 would be :-
P(number 7) =
Now Probability of this event = P(even numbers) × P(number 7)
Probability =
So final answer is .
Probability between z = 0 and z = 3.01 is given by
P(0<z<3.01) = P(z<3.01) - P(z<0)
Reading from the z-table, we have
P(z<0) = 0.5
P(z<3.01) = 0.9987
Hence, P(0<z<3.01) = 0.9987 - 0.5 = 0.4987
P(0<z<3.01) = P(z<3.01) - P(z<0)
Reading from the z-table, we have
P(z<0) = 0.5
P(z<3.01) = 0.9987
Hence, P(0<z<3.01) = 0.9987 - 0.5 = 0.4987