Let's first determine the total number of the students.
=> 10 freshman
=>12 sophomores
=>15 juniors
<span>=> 30 seniors in the club. </span>
Since the adviser will only chose 1, let's add then divide by 4 to get the average.
=> 10 + 12 +15 + <span>30 = 67 students
</span>=> 67 / 4 = 16.75
OR close to
<span>=> 15/67</span>
Answer:
B.
Step-by-step explanation:
Find the missing length by subtracting 5^2-3^2 to get 4^2.
Then do 4^2+7^2 to get 65
Eighteen cause 27 divided by 3 is 9. so 9 x 2 = 18
Given:
Total number of girls in her class = 16
Total number of boys in her class = 14
To find:
The number of different ways of choosing one girl and one boy.
Solution:
We have,
Total number of girls = 16
Total number of boys = 14
So,
Total number of ways to select one girl from 16 girls = 16
Total number of ways to select one boy from 14 boys = 14
Now, number of different ways of choosing one girl and one boy is
Therefore, the required number of different ways is 224.
For the four tickets and the rest of the prices seen up there, it would be $49.75, but if the problem meant that they bought EACH of something, then the total would be $64. :)