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Leona [35]
3 years ago
8

your father give you a plot for your god in which is 25 square meter and after awake you have planned only the 17 square meter o

f it what percentage of the plot is left to be plant​
Mathematics
2 answers:
user100 [1]3 years ago
8 0

Answer:

32%

Step-by-step explanation:

Total = 25

Planted = 17

Remaining = 25 - 17 = 8

8/25

= 0.32

= 32%

Verdich [7]3 years ago
3 0

\frac{25-17}{25}×100%%

=32%

∴ 32% is left to be plant.

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3 years ago
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Determine whether the lines are parallel, perpendicular or neither.
Firlakuza [10]

Answer:

Neither

Step-by-step explanation:

Although the lines intersect it is not at a 90° angle meaning it's neither perpendicular or parallel.

7 0
4 years ago
Write the standard form of the equation of the circle with endpoints of a diameter at the points (7,2) and (-9,5).
lys-0071 [83]

Answer:

(x+1)^2 + (y- 3.5)^2 =64

Step-by-step explanation:

We are given that  endpoints of a diameter at the points (7,2) and (-9,5).

Center of the circle is the mid point of diameter

So, first find the mid point of diameter

Formula : x=\frac{x_1+x_2}{2} , y=\frac{y_1+y_2}{2}

(x_1,y_1)=(7,2)\\(y_1,y_2)=(-9,5)

Substitute the values in formula

x=\frac{7-9}{2} , y=\frac{2+5}{2}

x=-1 , y=3.5

So, center of circle = (h,k )=(-1,3.5)

To find length of diameter :

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

(x_1,y_1)=(7,2)\\(y_1,y_2)=(-9,5)

d=\sqrt{(-9-7)^2+(5-2)^2}

d=\sqrt{265}

Length of radius = r = \frac{Diameter}{2}=\frac{\sqrt{256}}{2}

Standard form of the equation of the circle : (x -h)^2 + (y- k)^2 = r^2

(h,k )=(-1,3.5)

r=\frac{\sqrt{256}}{2}

Equation of the circle : (x+1)^2 + (y- 3.5)^2 =(\frac{\sqrt{256}}{2})^2

Equation of the circle : (x+1)^2 + (y- 3.5)^2 =64

Hence  the standard form of the equation of the circle with endpoints of a diameter at the points (7,2) and (-9,5) is  (x+1)^2 + (y- 3.5)^2 =64

5 0
4 years ago
An airplane flying at an altitude of 2600 m is approaching an airport run away located 56 km away (from the airplane to the run
Brrunno [24]

Given :

An airplane flying at an altitude of 2600 m is approaching an airport run away located 56 km away.

To Find :

The airplane’s angle of decent.

Solution :

Height of plane, h = 2600 m.

Horizontal distance of airplane from vertices is, d = 56 km = 56000 m.

Let, angle of depression is Ф.

So,

tan \ \phi = \dfrac{56000}{2600}\\\\tan \ \phi = 21.54\\\\\phi = 87.34^o

Therefore, the angle of decent is 87.34°.

Hence, this is the required solution.

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3 years ago
How you do this expression
lorasvet [3.4K]
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