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Grace [21]
3 years ago
12

As the [h+] in a solution decreases, what happens to the [OH^-]?

Chemistry
1 answer:
elixir [45]3 years ago
3 0

Explanation:

as the Hydrogen (acid) ion decreases there is a corresponding increase in the Hydroxide (basic) ion.

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If one mole of an unknown substance is 200.59 g/mole, what is the mass of 0.33 moles of that substance?
Nesterboy [21]

Answer: 66.83g

Explanation: (200.59 g/mole = Hg)

0.33 moles = 66.83g

5 0
3 years ago
What is the difference between the plasma and gaseous states of matter?
Ivenika [448]
In gaseous particles are slightly lighter than those in pasma which look like liquid
8 0
3 years ago
Emission results in the release of energy without any apparent change in mass or nuclear charge.
Sveta_85 [38]

Answer:

gamma ray

Explanation:

Gamma emission results in the release of energy without any apparent change in mass or nuclear charge.

Properties of Gamma radiations:

Gamma radiations are high energy radiations having no mass.

These radiations are travel at the speed of light.

Gamma radiations can penetrate into the many materials.

These radiations are also used to treat the cancer.

Lead is used for the protection  against gamma radiations because of its high molecular density.

The lead apron are used by the person when treated with gamma radiations.

Lead shields are also used in the wall, windows and doors of the room where gamma radiations are treated, in-order to protect the surroundings.

3 0
3 years ago
Three of the primary components of air are
Darya [45]

Answer:

125.681 torr

Explanation:

The formula to calculate the partial pressure of oxygen:

P(O2) = Pcommon - PCO2 - PN2

1 atm = 760 torr

Therefore you need to find the partial pressure of oxygen:

P(O2) = 760 torr -0.285 torr - 634.034 torr =130.013 torr

- Hope that helped!

8 0
3 years ago
When 28 g of nitrogen and 6 g of hydrogen react, 34 g of ammonia are produced. if 100 g of nitrogen react with 6 g of hydrogen,
vampirchik [111]
N2 + 3H2 --> 2NH3
When 100g of N2 , no of moles of N2= 100/(28)=3.57 mol
no. of moles of h2 = 6/(2)=3mol
Therefore h2 is limiting reagent.
no. of moles of ammonia= 3/3*2=2moles
mass of ammonia produced= 2 mol * (14+3)= 34g
4 0
2 years ago
Read 2 more answers
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