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3 years ago

PLS HELP! ANSWER ONLY IF YOU KNOW!

Mathematics

1 answer:

Norma-Jean [14]3 years ago

5 0

Answer: The answer is -1 to 2 with open points

This is for both functions check picture below

Step-by-step explanation:

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Solve the following inequality for c. Write your answer in the simplest form. 1+4(8c-6)<-6c-10-1

Damm [24]

$\frac{x}{y} 6/19\\$ Answer:

c < 6/19

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Anyone know how to do it?

Oksana_A [137]

1) is f= x(58) x being each hour and 58 being the amount of flyers in each hour combine for less of a headache.

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4) this is kinda a guess but I think it's 57 mins and 2 seconds. try checking

8 0

3 years ago

The functions f(x) = -(x+4) +2 and g(x) =(x-2)^2 -2 have been rewritten using the completing the square method. Apply your knowl

rewona [7]

Answer:

$g(x) = (x-2)^2 -2$

If we compare this function with the vertex form we see that:

$a = 1, h =2, k =-2$

So then the vertex would be $(h,k)=(2,-2)$

And since the value for a is positive we know that the parabola open upward. We don't have a maximum defined since open upwards and the minimum point correspond to the vertex on this case (2,-2).

$f(x)= -(x+4)^2 +2$

If we compare this function with the vertex form we see that:

$a=-1, h =-4, k = 2$

And since the value for a is negative we know that the parabola open downward. We don't have a minimum defined since open downwards and the maximum point correspond to the vertex on this case (-4,2).

Step-by-step explanation:

We need to remember that the standard form for a parabola is given by the following equation:

$y = ax^2 + bx +c$

And the vertex form is given by this formula:

$y = a(x-h)^2 +k$

And we want to find the vertex and if we have a maximum or minimum for each function. Let's begin with g(x)

$g(x) = (x-2)^2 -2$

If we compare this function with the vertex form we see that:

$a = 1, h =2, k =-2$

So then the vertex would be $(h,k)=(2,-2)$

And since the value for a is positive we know that the parabola open upward. We don't have a maximum defined since open upwards and the minimum point correspond to the vertex on this case (2,-2).

For the function f(x) we assume that we have the following equation:

$f(x)= -(x+4)^2 +2$

If we compare this function with the vertex form we see that:

$a=-1, h =-4, k = 2$

And since the value for a is negative we know that the parabola open downward. We don't have a minimum defined since open downwards and the maximum point correspond to the vertex on this case (-4,2).

4 0

3 years ago

Please help find a formula of the function

luda_lava [24]

Well for a linear function you would use the formula y=mx+b

7 0

3 years ago

Someone please help, 100 points.

Over [174]

Part 1
Let:
y be the total cost
x be the number of tickets
a be fair admission

Since the fair charges $1.25 per ticket, the equation of the line would look like:

y = 1.25x + a

Since Johnny spent $43.75 and bought 25 tickets, we find a by replacing y with 43.75 and x with 25:

43.75 = 1.25×25 + a

Now solve for a

43.75 = 31.25 + a
43.75 - 31.25 = a
a = 12.50

Going back to the first equation:

y = 1.25x + 12.50

Part 2:
a) Let (9,8) be (x1,y1) and (4,-12) be (x2,y2)
The formula for slope is:
$m = \frac{y2 - y1}{x2 - x1} \\ m = \frac{ - 12 - 8}{4 - 9} \\ m = \frac{ - 20}{ - 5} \\ m = 4$
b) For the point-slope equation, I'll use (9,8)
Using the formula:
$y - y1 = m(x - x1) \\ y - 8 = 4(x - 9)$
c) For the slope-intercept form, we solve for y in the point-slope formula:
$y - 8 = 4(x - 9) \\ y = 4x - 36 + 8 \\ y = 4x - 28$

5 0

3 years ago