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Elan Coil [88]
3 years ago
6

How is bacteria on mars counted as life but a heartbeat on earth is not?

Chemistry
1 answer:
Pani-rosa [81]3 years ago
4 0
Because if you get bacteria you will die and a heartbeat is basically how your living...
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The net force on a vehicle that is accelerating at a rate of 1.15 m/s2
Softa [21]

Answer:

<h2>1565.2 kg</h2>

Explanation:

The mass of the vehicle can be found by using the formula

m =  \frac{f}{a}  \\

f is the force

a is the acceleration

From the question we have

a =  \frac{1800}{1.15}  \\  = 1565.217...

We have the final answer as

<h3>1565.2 kg</h3>

Hope this helps you

7 0
3 years ago
Find the molarity of a solution in which 0.99 mol of NaCl are dissolved in 2.5 L of solution.
rusak2 [61]

Answer:

0.369M

Explanation:

\boxed{Molarity = mole \div volume}

☆ Volume has to be in litres

Molarity of solution

= 0.99 ÷2.5

= 0.369 M

3 0
3 years ago
A frying pan is connected to a 110-volt circuit. If the resistance of the frying pan is 10 ohms, how many amperes does the fryin
iogann1982 [59]

Answer:

<u>11 A</u>

Explanation:

⇒ V = IR

⇒ 110 V = I * 10 Ω

⇒ I = 110/10

⇒ I = <u>11 A</u>

6 0
2 years ago
C8H10N4O2 is the chemical formula for caffeine. List the 3 remaining elements in caffeine and how many atoms of that element are
velikii [3]
No idea , sorry. maybe it is.....actually i dont know, sooo sorry
7 0
3 years ago
The half-life of Palladium-100 is 4 days. After 12 days a sample of Palladium-100 has been reduced to a mass of 4 mg. What was t
Degger [83]

Answer : The initial mass of the sample is, 31.9 mg

Explanation :

Half-life = 4 days

First we have to calculate the rate constant, we use the formula :

k=\frac{0.693}{t_{1/2}}

k=\frac{0.693}{4\text{ days}}

k=0.173\text{ days}^{-1}

Now we have to calculate the initial mass of sample.

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 0.173\text{ days}^{-1}

t = time passed by the sample  = 12 days

a = initial amount of the reactant  = ?

a - x = amount left after decay process = 4 mg

Now put all the given values in above equation, we get

12=\frac{2.303}{0.173}\log\frac{a}{4}

a=31.9mg

Therefore, the initial mass of the sample is, 31.9 mg

3 0
3 years ago
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