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DochEvi [55]
3 years ago
10

What is the hydronium h3o+ concentration of a solution with a pH pf 3

Chemistry
1 answer:
arlik [135]3 years ago
7 0

Answer:

1x10^-3M

Explanation:

Data obtained from the question include:

pH = 3

[H3O+] =?

The concentration of the hydronium ion [H3O+] can be obtained by using the formula pH = - Log [H3O+] as illustrated below:

pH = - Log [H3O+]

3 = - Log [H3O+]

Divide through by - 1

- 3 = Log [H3O+]

Take the anti-log of - 3

[H3O+] = 1x10^-3M

Therefore, the concentration of the hydronium ion [H3O+] is 1x10^-3M

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Answer:

it binds molecules like a chemical bond-breaking

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Enzymes perform the critical task of lowering a reaction's activation energy—that is, the amount of energy that must be put in for the reaction to begin. Enzymes work by binding to reactant molecules and holding them in such a way that the chemical bond-breaking and bond-forming processes take place more readily.

3 0
3 years ago
A sample of glucose ( C6H12O6 ) of mass 8.44 grams is dissolved in 2.11 kg water. What is the freezing point of this solution? T
zhuklara [117]

Answer:

- 0.0413°C ≅ - 0.041°C (nearest thousands).

Explanation:

  • Adding solute to water causes the depression of the freezing point.

  • We have the relation:

<em>ΔTf = Kf.m,</em>

Where,

ΔTf is the change in the freezing point.

Kf is the freezing point depression constant (Kf = 1.86 °C/m).

m is the molality of the solution.

<em>Molality is the no. of moles of solute per kg of the solution.</em>

  • <em>no. of moles of solute (glucose) = mass/molar mass</em> = (8.44 g)/(180.156 g/mol) = <em>0.04685 mol.</em>

<em>∴ molality (m) = no. of moles of solute/kg of solvent</em> = (0.04685 mol)/(2.11 kg) = <em>0.0222 m.</em>

∴ ΔTf = Kf.m = (1.86 °C/m)(0.0222 m) = 0.0413°C.

<em>∴ The freezing point of the solution = the freezing point of water - ΔTf </em>= 0.0°C - 0.0413°C = <em>- 0.0413°C ≅ - 0.041°C (nearest thousands).</em>

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Which chemical equation is correctly balanced?
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3 years ago
Read 2 more answers
When the enthalpy of the reaction is provided, it is always in the context of moles; i.e., ΔHrxn=+252.8 kJ when two moles of CH3
Morgarella [4.7K]

<u>Answer:</u> The balanced chemical equation is written below.

<u>Explanation:</u>

There are 2 types of chemical reaction classified on the basis of heat change:

  • <u>Endothermic reactions </u>: They are the reactions in which energy of products is more than the energy of the reactants. For these reactions, energy is absorbed by the system. The \Delta H comes out to be positive and is written on the reactants side.
  • <u>Exothermic reactions:</u> They are the reactions in which energy of reactants is more than the energy of the products. For these reactions, energy is released by the system. The \Delta H comes out to be negative and is written on the product side.

We are given:

Moles of methanol = 2 moles

Moles of methane = 2 moles

Moles of oxygen gas = 1 mole

\Delta H_{rxn}=+252.8kJ

The chemical equation follows:

2CH_3OH+252.8kJ\rightarrow 2CH_4+O_2

Hence, the balanced chemical equation is written above.

4 0
4 years ago
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