Answer:
(a) Homogeneous. 4.7 g of MgCl₂.
(b) 9.1 g
Explanation:
(a)
At 200°C, we can dissolve 54.6g of MgCl₂ in 100 g of water. The mass that we could dissolve in 38.2 g of water is:
Since we can dissolve up to 20.9 g of MgCl₂ and we added only 16.2 g, the mixture is homogeneous and we could add 20.9 g -16.2 g = 4.7 g of solute to make it saturated.
(b)
At 800°C, we can dissolve 66.1 g of MgCl₂ in 100 g of water. The mass that we could dissolve in 38.2 g of water is:
Since we can dissolve up to 25.3 g of MgCl₂ and we added only 16.2 g, we could add 25.3 g - 16.2 g = 9.1 g of solute to make it saturated.
Answer:
According to Le Chatelier’s Principle, a stress placed on a system at equilibrium will cause the equilibrium to shift to counteract the stress. For example, a temperature increase in the above reaction will favor the reverse reaction to use the excess heat and form brown NO2 gas. A temperature decrease in the above reaction favors the forward reaction to produce heat and form colorless N2O4 gas.
Answer:
The magnesium reacted with the oxygen in the air.
Explanation:
For argument’s sake, let’s say that the mass of magnesium oxide was 3 g and that of the oxide was 5 g.
The reaction was
magnesium + oxygen ⟶ magnesium oxide
Mass: 3 g 5 g
Mass of oxygen = 5 g – 3 g = 2 g
The 3 g of magnesium must have combined with 2 g of oxygen to form 5 g of magnesium oxide.
To segregate p-tert-butylphenol after you have removed it into NaOH arrangement one would accelerate the p-tert-butylphenol by adding 3M HCl to the cooled arrangement until the point when it is acidic. At that point as the phenol isolates as an oil, one needs to cool the blend in an ice shower to encourage crystallization. The precious stones that are then framed are the p-tert-butylphenol which can be isolated from the arrangement by filtration utilizing the Hirsch pipe
Answer:
Ba -> Ba2+ + 2e-
Explanation:
A neutral atom becomes an iron when that atom loses electrons. The number of electroms lost by that atom determines the ionic charge or charge of it's ion. In this case, a neutral Barium atom (Ba) will become a barium ion, which has a charge of +2, when it loses 2 electrons to a more electronegative atom in a reaction.
The equation is:
Ba -> Ba2+ + 2e-
2e- is the two electrons lost
