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Kaylis [27]
4 years ago
11

14.   Simplify (4x^– 4)^– 3.

Mathematics
1 answer:
Luda [366]4 years ago
8 0
(4x^{-4})^{-3}=4^{-3}\cdot x^{12}=\dfrac{x^{12}}{64}
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3 years ago
Find the derivatives of the following implicit function
ddd [48]

Answer:

\frac{d}{dx}\left(y\right)=\frac{2-6x+6y}{-6x+2y+1}

Step-by-step explanation:

3x^2-6xy+y^2=2x-y\\\mathrm{Treat\:}y\mathrm{\:as\:}y\left(x\right)\\\mathrm{Differentiate\:both\:sides\:of\:the\:equation\:with\:respect\:to\:}x\\\frac{d}{dx}\left(3x^2-6xy+y^2\right)=\frac{d}{dx}\left(2x-y\right)\\\frac{d}{dx}\left(3x^2-6xy+y^2\right)=6x-6\left(y+x\frac{d}{dx}\left(y\right)\right)+2y\frac{d}{dx}\left(y\right)\\\frac{d}{dx}\left(2x-y\right)=2-\frac{d}{dx}\left(y\right)\\6x-6\left(y+x\frac{d}{dx}\left(y\right)\right)+2y\frac{d}{dx}\left(y\right)=2-\frac{d}{dx}\left(y\right)

\mathrm{For\:convenience,\:write\:}\frac{d}{dx}\left(y\right)\mathrm{\:as\:}y^{'\:}\\6x-6\left(y+xy^{'\:}\right)+2yy^{'\:}=2-y^{'\:}\\\mathrm{Isolate}\:y^{'\:}:\quad y^{'\:}=\frac{2-6x+6y}{-6x+2y+1}\\y^{'\:}=\frac{2-6x+6y}{-6x+2y+1}\\\mathrm{Write}\:y^{'\:}\:\mathrm{as}\:\frac{d}{dx}\left(y\right)\\\frac{d}{dx}\left(y\right)=\frac{2-6x+6y}{-6x+2y+1}

3 0
3 years ago
I want to solve this equation (x+2)^2
olchik [2.2K]
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I hope this helped!
<em>~cupcake</em>
7 0
4 years ago
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