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3 years ago

Graph the following piecewise function:

Mathematics

1 answer:

zhenek [66]3 years ago

5 0

Check the picture below.

notice the solid circle at -4 and 3, since it includes those points.

also notice the dashed line, though the lines keeps on going those ways, is not included in the piece-wise, since it's not part fo the domain or constraints.

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( 9 x − 4 ) + 3 ( 8 x − 2 )

weeeeeb [17]

Answer:

17x-3

Step-by-step explanation:

This is the answer only if u are trying to add kk

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2 years ago

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PLEASE HELP!!!!!!!!!!!!! DUE SOON

Sergio039 [100]

$\bf ~~~~~~\textit{initial velocity} \\\\ \begin{array}{llll} ~~~~~~\textit{in feet} \\\\ h(t) = -16t^2+v_ot+h_o \end{array} \quad \begin{cases} v_o=\stackrel{}{\textit{initial velocity of the object}}\\\\ h_o=\stackrel{}{\textit{initial height of the object}}\\\\ h=\stackrel{}{\textit{height of the object at "t" seconds}} \end{cases} \\\\[-0.35em] ~\dotfill\\\\ h=-16t^2+\stackrel{\stackrel{v_o}{\downarrow }}{65}t$

now, take a look at the picture below, so for 2) and 3) is the vertex of this quadratic equation, 2) is the y-coordinate and 3) the x-coordinate.

$\bf \textit{vertex of a vertical parabola, using coefficients} \\\\ h=\stackrel{\stackrel{a}{\downarrow }}{-16}t^2\stackrel{\stackrel{b}{\downarrow }}{+65}t\stackrel{\stackrel{c}{\downarrow }}{+0} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right) \\\\\\ \left( -\cfrac{65}{2(-16)}~~,~~0-\cfrac{65^2}{4(-16)} \right) \implies \left( \cfrac{65}{32}~,~0- \cfrac{4225}{-64}\right)$

$\bf \left( \cfrac{65}{32}~,~0+ \cfrac{4225}{64}\right)\implies \left( \stackrel{seconds}{2\frac{1}{32}}~~,~~ \stackrel{feet~hight}{66\frac{1}{64}}\right)$

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2 years ago

What is the simplified expression for 4 power 4 multiplied by 4 power 3 over 4 power 5? (1 point)

raketka [301]

The solution to the problem is 16.

first, you must set up the equation.

$4^4*\frac{4^3}{4^5}$

Then, simplify exponents.

256* $\frac{64}{1024}$

Next, simplify the equation.

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2 years ago

A chain fits tightly around two gears as shown. What is the radius of the smaller gear? Round your answer to the nearest tenth.

GrogVix [38]

Using the Pythagorean theorem we can solve for the radius

see attached picture:

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2 years ago

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Find an equation of the tangent line to the hyperbola: x^2/a^2 - y^2/b^2 = 1 at the point (x0,x1)

musickatia [10]

The standard form of a hyperbola is x2/a2 − y2/ b2 = 1
the tangent line is the first derivative of the functiony′ = b^2x/ a^2 y
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Therefore the equation of the tangent line isy−x1 = b^2 x0 / a^2 x1* (x−x0)

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2 years ago