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topjm [15]
3 years ago
15

Sam traveled 56 miles in 8 hours. If he traveled at the same rate on the next day,how far can he go the next day,how far could h

e go in 14 hours.​
Mathematics
1 answer:
lutik1710 [3]3 years ago
8 0

Answer:

Step-by-step explanation:

56 miles/(8 hours) = 7 miles/hour

14 hours × 7 miles/hour = 98 miles

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Plsss help, will reward brainliest!!! Thank you.<br><br><br><br> Look at picture^^^
Step2247 [10]

Answer:

-2b and -0.9b and b/12

Step-by-step explanation:

6 0
3 years ago
Please help <br> I will mark brainlist
Naya [18.7K]

Answer:

B x = sqrt(48)

Step-by-step explanation:

Half of the bottom side measures 4.

4^2 + x^2 = 8^2

16 + x^2 = 64

x^2 = 48

x = sqrt(48)

Answer: B x = sqrt(48)

4 0
3 years ago
Find the answer for x that makes this number sentence true: 2x + 9 &gt; 11
Nana76 [90]

Answer:

2 x <u>2</u> + 9 > 11

2 x 2 = 4

4 + 9 = 13

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Therefore, x = 2.

Step-by-step explanation:

I hope this helps! ^w^

3 0
2 years ago
19 there is a frog and snake exhibit at
Norma-Jean [14]

Answer:

b.42

Step-by-step explanation:

the ratiois is 3 to 4 .So every 4 snakes is to 3 frogs so since there are 24 snakes devide the 24 by 4 which will give u 6 then multiply the answer by 3 which will give u 18 which represents the total number of frogs then add 18 +24 which is 42.

so then total number of frogs is 42.

5 0
2 years ago
So this has to do with permutations and honestly I need an explanation on how I can figure these out.
AnnZ [28]
Well, the answer quite simple ....there are 4! ways to arrange these numbers...and as 4! = 4*3*2*1 = 24

hence 24 is the correct answer....


u can also remember it by theorem of multiplication as.....in first place (I.e. first code can be any no. out of 4,5,2&7 ....so 4*.....

as first place is acquired by a certain no. that leaves three no. to fill third place and when third place I'd occupied it leaves 2 numbers to fill second place and lastly only one no. to fill the last place .....so it's result will be like 4*3*2*1.



I know this is pretty much confusing ....but still I tried my best....

if anything troubles u here feel free to ask me
6 0
3 years ago
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