Im sick and tired of reposting my question over and over again. So please if any of you real people would help me I would feel b
etter
1 answer:
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Answer:
16 ft²
Step-by-step explanation:
The complete question is attached.
A trapezoid is a quadrilateral (has four sides) with one a parallel base. The base angles and the diagonals of an isosceles trapezoid are equal.
The area of a trapezoid = [(sum of the parallel bases) / 2] * height of the trapezoid.
Given that the parallel bases are 3 ft and 5 ft, while the height of the trapezoid is 4 ft. Hence:
The area of a trapezoid = [(3 + 5)/2] * 4
The area of a trapezoid = 16 ft²
Answer:
A ) Not orthogonal to each other
B) 50i + 40j + 105k
C) The tensor product is attached below
D ) The value of X = F.X is attached below
Step-by-step explanation:
attached below is the detailed solution of the above problem
A) for the vectors ( u ) and ( v ) to be orthogonal to each other [ U.V has to be = 0 ] but in this scenario U.V = 4 hence they are not orthogonal to each other
b) The vector normal to plane is gotten by : U x V
= 50i + 40j + 105k
