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2 years ago

To be effective, a certain drug must not drop below 15 mg in the body. A 120

1 answer:

6 0

Thus, it follows that after 4 to 5 half-lives, the plasma concentrations of a given drug will be below a clinically relevant concentration and thus will be considered eliminated. Conversely, the accumulation of a drug can reach a steady-state during an infusion

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Atomic radius increases as you move down a group of elements.

raketka [301]

Yes, the atomic radius increases as you move down a group of elements. this is true
going down leads to valence electrons that are further away from nucleus -> less electrostatic attraction -> less pull towards nuc. -> greater radius/volume taken

3 0

2 years ago

When 1 mol of KBr(s) decomposes to its elements, 394 kJ of heat is absorbed. (a) Write a balanced thermochemical equation.

VladimirAG [237]

The balanced thermochemical equation is

KBr ------- K + 1/2 Br2

<h3>What is thermochemical equation? </h3>

A Thermochemical Equation is defined as the balanced stoichiometric chemical equation which includes the enthalpy change, ΔH.

The chemical equation for the decomposition of potassium bromide to its constituent elements bromine ans potassium :

KBr ----- K + Br2

The balanced thermochemical equation of the decomposition of potassium bromide to its constituent elements potassium and bromide as follows

KBr ------- K + 1/2 Br2

As the heat is absorbed in this reaction therefore, heat is positive.

Thus, we concluded that the balanced thermochemical equation is

KBr ------- K + 1/2 Br2

learn more about thermochemical equation:

brainly.com/question/2733624

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8 0

1 year ago

If 97.3 L of NO2 forms measured at 35 C and 632 mm Hg. What is the percent yield?

enyata [817]

<span>a. Use PV = nRT and solve for n = number of mols O2.
mols NO = grams/molar mass = ?

Using the coefficients in the balanced equation, convert mols O2 to mols NO2. Do the same for mols NO to mols NO2. It is likely that the two values will not be the same which means one is wrong; the correct value in LR (limiting reagent) problems is ALWAYS the smaller value and the reagent producing that value is the LR.

b.
Using the smaller value for mols NO2 from part a, substitute for n in PV = nRT, use the conditions listed in part b, and solve for V in liters. This will give you the theoretical yield (YY)in liters. The actual yield at these same conditions (AY) is 84.8 L.

</span>and % will be 60%.

3 0

2 years ago

How many kilojoules of heat are released when 0.72 mole of oxygen gas are used to combust methane?

KonstantinChe [14]

0.72 mole of oxygen would produce 320.4 kJ of heat.

<u>Explanation:</u>

CH₄ (g) + 2O₂ (g) → CO₂ (g) + 2H₂O (ℓ) + 890kJ

According to the equation,

2 moles of O₂ produces 890 kJ of heat

So, 0.72 moles of O₂ will produce:

$= \frac{890}{2} X 0.72\\\\= 445 X 0.72\\\\= 320.4 kJ$

Therefore, 0.72 mole of oxygen would produce 320.4 kJ of heat.

6 0

3 years ago

Oxygen has 6 valence electrons. how many hydrogen atoms (who have 1 valence electrons) can bond with it? remember the octet rule

Stella [2.4K]

Answer:

two hydrogen can bonded with oxygen to form H2O

5 0

3 years ago