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2 years ago

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1 answer:

dolphi86 [110]2 years ago

8 0

Answer: D. transverse

Explanation:

Light is a transverse wave, while sound is a longitudinal wave.

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Beta particles are identical to Multiple Choice protons. helium atoms. hydrogen atoms. helium nuclei.

Vesna [10]

Correct option:

Beta particles are identical to "electrons".

What are particle beams:

There are various types of particle beams, such as (alpha) and (beta) particles, neutron beams, etc. While β-particles are electrons released from a nucleus, helium nuclei made up of two protons and two neutrons are known as α-particles.

When certain radionuclides undergo a process known as beta-decay, high-energy, high-speed electrons (e-) or positrons (p+) are released from the nucleus.

An electron and a beta particle share the same mass and charge.

Beta radiation in high doses can burn the skin, and beta emitters are dangerous if they penetrate the body. Thin sheets of metal or plastic may be able to stop beta particles.

Note: Your question is incomplete, but most probably your full question also includes one more option "Electron".

Beta particles are identical to

Multiple Choice

1. protons. 2. helium atoms. 3. hydrogen atoms. 4. helium nuclei. 5. electrons.

Learn more about the beta particles here,

brainly.com/question/3580345

#SPJ4

4 0

2 years ago

Please help !!!!!!!!!!!

Sindrei [870]

Answer:

Iron wood is very dense and will sink in water. B

Explanation:

Hope this helps!!

6 0

2 years ago

Read 2 more answers

evablogger [386]

True is your answer so true

6 0

3 years ago

Read 2 more answers

When 92.0 g of ethanol (c2h5oh are vaporized at its boiling point of 78.3°c, it requires 78.6 kj of energy. what is the approxim

Juli2301 [7.4K]

The solution would be like this for this specific problem:

<span>(78.6 kJ) / (92.0 g / (46.0684 g C2H5OH/mol)) = 39.4 kJ/mol </span>

<span>39.3 </span>

So the approximate molar heat of vaporization of ethanol in kJ/mol is 39.3.

I hope this answers your question.

7 0

3 years ago

Read 2 more answers

Cobalt-60 is a strong gamma emitter that has a half- life of 5.26 yr. The co balt-60 in a radiotherapy unit must be replaced whe

Alenkasestr [34]

<u>Answer:</u> The sample of Cobalt-60 isotope must be replaced in January 2027

<u>Explanation:</u>

The equation used to calculate rate constant from given half life for first order kinetics:

$t_{1/2}=\frac{0.693}{k}$

where,

$t_{1/2}$ = half life of the reaction = 5.26 years

Putting values in above equation, we get:

$k=\frac{0.693}{5.26yrs}=0.132yrs^{-1}$

Rate law expression for first order kinetics is given by the equation:

$k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}$

where,

k = rate constant = $0.132yr^{-1}$

t = time taken for decay process = ? yr

$[A_o]$ = initial amount of the sample = 100 grams

[A] = amount left after decay process = (100 - 75) = 25 grams

Putting values in above equation, we get:

$0.132=\frac{2.303}{t}\log\frac{100}{25}\\\\t=10.5yrs$

The original sample was purchased in June 2016

As, June is the 6th month of the year, which means the time period will be $2016+\frac{6}{12}=2016.5$

Adding the time in the original time period, we get:

$2016.5+10.5=2027$

Hence, the sample of Cobalt-60 isotope must be replaced in January 2027

3 0

3 years ago