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melisa1 [442]
1 year ago
7

Which electron is, on average, close to the nucleus: an electron in a 2s orbital or an electron in a 3s orbital?

Chemistry
1 answer:
valina [46]1 year ago
6 0

electron is, on average, close to the nucleus: an electron in a 2s orbital or an electron in a 3s orbital is electrons . The electron in 2s orbital are closer to the nucleus than those of 3s orbital.

The 3s orbital electron posses more energy than those electrons in  2s orbital. The size of orbital is determine by the principal quantum number n. The higher the value of n , the farther the orbital from the nucleus . And same as the electron situated to orbital.

Thus, electron is, on average, close to the nucleus: an electron in a 2s orbital or an electron in a 3s orbital is electrons . The electron in 2s orbital are closer to the nucleus than those of 3s orbital.

To learn more about orbital here

brainly.com/question/18914648

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4 years ago
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Which metal ion was green when placed in the fire?
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Answer:

Barium Ba2+

Explanation:

Potassium lilac

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3 years ago
What is the periodic table, and what is its significance in the study of chemistry?
NeX [460]

Explanation:

<u>Periodic table is the tabular display of elements that are arranged by the increasing atomic number. </u>

Structure of the periodic table shows various periodic trends.

<u>Significance: </u>

The periodic table is very important because it gives an organized way to provide lots of information about the elements and how they can be related to one another. The table gives a systematic approach to study the elements and their properties. The table can also be used to predict the properties of the elements which have not been discovered yet.

6 0
4 years ago
What is the wavelength of radiation that has a frequency of 5.9×1011 s−1 ?
Igoryamba

Answer:

frequency = velocity of light /wavelength

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3 0
3 years ago
The rate constant of a reaction is 4.7×10−3 s−1 at 25°C, and the activation energy is 33.6 kJ/mol. What is k at 75°C?
vodomira [7]

Answer:

k is 3,18*10⁻² s⁻¹ at 75°C

Explanation:

following Arrhenius equation:

k= k₀*e^(-Ea/RT)

where k= rate constant , k₀= frequency factor , Ea= activation energy , R= universal gas constant T=absolute temperature

then for T₁=25°C =298 K

k₁= k₀*e^(-Ea/RT₁)

and for T₁=75°C = 348 K

k₂= k₀*e^(-Ea/RT₂)

dividing both equations

k₂/k₁= e^(-Ea/RT₂+Ea/RT₁ )

k₂= k₁*e^[-Ea/R*(1/T₂-1/T₁ )]

replacing values

k₂= k₁*e^[-Ea/R*(1/T₂-1/T₁ )] = 4,7*10⁻³ s⁻¹ *e^[-33.6*1000 J/mol /8.314 J/molK*(1/ 348 K -1/298 K )] = 3,18*10⁻² s⁻¹

thus k is 3,18*10⁻² s⁻¹ at 75°C

6 0
4 years ago
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