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1 year ago

Which electron is, on average, close to the nucleus: an electron in a 2s orbital or an electron in a 3s orbital?

1 answer:

6 0

electron is, on average, close to the nucleus: an electron in a 2s orbital or an electron in a 3s orbital is electrons . The electron in 2s orbital are closer to the nucleus than those of 3s orbital.

The 3s orbital electron posses more energy than those electrons in 2s orbital. The size of orbital is determine by the principal quantum number n. The higher the value of n , the farther the orbital from the nucleus . And same as the electron situated to orbital.

Thus, electron is, on average, close to the nucleus: an electron in a 2s orbital or an electron in a 3s orbital is electrons . The electron in 2s orbital are closer to the nucleus than those of 3s orbital.

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What is the number of atoms per unit cell for each metal? (c) Silver, Ag

katrin2010 [14]

Silver (Ag) is the number of atoms per unit cell for each metal. Silver has a face-centred cubic (FCC) unit cell structure, where there are 8 corner atoms and 6 atoms on the faces, so there are a total of 4 atoms per unit cell.

The identical unit cells are defined in such a way that they take up space without touching one another. A crystal's internal 3D arrangement of atoms, molecules, or ions is known as its lattice. It consists of a large number of unit cells. Every point of the lattice is occupied by one of the three component particles.

Primitive cubic, body-centred cubic (BCC), and face-centred cubic are the three types of unit cells (FCC). The three different sorts of unit cells will be thoroughly covered in this section.

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5 0

1 year ago

Chloroform is a liquid once used for anesthetic. What is the volume of 5.0 g of chloroform? The density of chloroform 1.49 g/mL

mario62 [17]

Answer:

3.3557047 mL

Explanation:

The density can be found using the following formula:

$d=\frac{m}{v}$

Let's rearrange the formula to find the volume, $v$ .

$d*v=\frac{m}{v}*v$

$d*v=m$

$\frac{d*v}{d} =\frac{m}{d}$

$v=\frac{m}{d}$

The volume can be found by dividing the mass by the density. The mass of the chloroform is 5 grams and the density is 1.49 grams per milliliter. Therefore,

$m= 5g \\d= 1.49 g/mL$

Substitute the values into the formula.

$v=\frac{5g}{1.49 g/mL}$

Divide. When we divide, the grams, or g, in the numerator and denominator will cancel out.

$v= \frac{5}{1.49}mL$

$v=3.3557047 mL$

The volume of 5 grams of chloroform is 3.3557047 milliliters

4 0

3 years ago

What is the pH of a solution has a hydrogen ion concentration of 6.3 x 10–10 M? Show work

NISA [10]

Answer:

pOH = 4.8

pH = 9.2

Explanation:

Given data:

Hydrogen ion concentration = 6.3×10⁻¹⁰M

pH of solution = ?

pOH of solution = ?

Solution:

Formula:

pH = -log [H⁺]

[H⁺] = Hydrogen ion concentration

We will put the values in formula to calculate the pH.

pH = -log [6.3×10⁻¹⁰]

pH = 9.2

To calculate the pOH:

pH + pOH = 14

We will rearrange this equation.

pOH = 14 - pH

now we will put the values of pH.

pOH = 14 - 9.2

pOH = 4.8

7 0

3 years ago

A cube of plastic 1.2x10^-5 km on a side has a mass of 1.1 g. what is its density in g/cm^3

Vesna [10]

Length of 1 side 1.2*10^-5km =1.2*10^-5*10^5 =1.2cm

volume of the cube (1.2)^3=1.728 cm^3 

density= mass/volume= 1.1/1.728=0.636 g/cm^3

7 0

3 years ago

Read 2 more answers

Calculate the number of moles of magnesium, chlorine, and oxygen atoms in 5.90 moles of magnesium perchlorate, Mg(ClO4)2.

Lady bird [3.3K]

Answer:

5.90, 11.8, 47.2

Explanation:

Let’s remove the parentheses and write the formula as MgCl₂O₈.

We see that 1 mol Mg(ClO₄)₂ contains 1 mol Mg atoms, 2 mol Cl atoms, and 8 mol O atoms.

∴ $\text{Moles of Mg atoms} = \text{5.90 mol Mg(ClO}_{4})_{2} \times \frac{\text{1 mol Mg atoms}} {\text{1 mol Mg(ClO}_{4})_{2}} = \text{5.90 mol Mg atoms}$

$\text{Moles of Cl atoms} = \text{5.90 mol Mg(ClO}_{4})_{2} \times \frac{\text{2 mol Cl atoms}} {\text{1 mol Mg(ClO}_{4})_{2}} = \text{11.8 mol Cl atoms}$

$\text{Moles of O atoms} = \text{5.90 mol Mg(ClO}_{4})_{2} \times \frac{\text{8 mol O atoms}} {\text{1 mol Mg(ClO}_{4})_{2}} = \text{47.2 mol O atoms}$

∴ Mg, Cl, O = 5.90, 11.8, 47.2

4 0

3 years ago