Answer:
what exactly is the question to the problem ? it looks like it's already solved ? are you suppose to find something or ?
Given:
In the circle, 
and 
.
To find:
The following measures:
(a) 
(b) 
Solution:
According to the central angle theorem, the central angle is always twice of the subtended angle intercepted on the same same arc.
In a cyclic quadrilateral, the opposite angles are supplementary angles.
UVWX is a cyclic quadrilateral. So,
[Opposite angles of a cyclic quadrilateral]
Now,
[Opposite angles of a cyclic quadrilateral]
Therefore, and .
1/5( 5/2 x 4/7 -11/7) + 3/28
Multiply the terms (5/2 x 4/7) in bracket then subtract it from 11/14. Result will be 10/7.
Then multiply 1/5 with 10/7. The result will be 2/7.
2/7 + 3/28 = 11/28
T
Answer:
70.2 x 10=702.
6.702 x 10=67.02
7.02 x 100=70.2
7.02 x 10=70.2
Step-by-step explanation:
I hope this help! :)
