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2 years ago

Which equation can be used to find 42x51?

Mathematics

1 answer:

kirza4 [7]2 years ago

5 0

Answer:

(40 x 50) + (2 x 1) = 2,000 + 2

Step-by-step explanation:

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Sadie sold 45 cupcakes, which were packed in 9 boxes. How many cupcakes were in each box? 4 5 8 9

Korvikt [17]

45 divided by 9 = 5
5 cupcakes per box

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3 years ago

Read 2 more answers

20 days to 2 weeks ratio

Andreas93 [3]

Answer:

20:14 = 10:7

Step-by-step explanation:

A week is equal to 7 days

2 weeks is equal to 2*7 = 14 days

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3 years ago

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This is finding exact values of sin theta/2 and tan theta/2. I’m really confused and now don’t have a clue on how to do this, pl

Lostsunrise [7]

First,

tan(θ) = sin(θ) / cos(θ)

and given that 90° < θ < 180°, meaning θ lies in the second quadrant, we know that cos(θ) < 0. (We also then know the sign of sin(θ), but that won't be important.)

Dividing each part of the inequality by 2 tells us that 45° < θ/2 < 90°, so the half-angle falls in the first quadrant, which means both cos(θ/2) > 0 and sin(θ/2) > 0.

Now recall the half-angle identities,

cos²(θ/2) = (1 + cos(θ)) / 2

sin²(θ/2) = (1 - cos(θ)) / 2

and taking the positive square roots, we have

cos(θ/2) = √[(1 + cos(θ)) / 2]

sin(θ/2) = √[(1 - cos(θ)) / 2]

Then

tan(θ/2) = sin(θ/2) / cos(θ/2) = √[(1 - cos(θ)) / (1 + cos(θ))]

Notice how we don't need sin(θ) ?

Now, recall the Pythagorean identity:

cos²(θ) + sin²(θ) = 1

Dividing both sides by cos²(θ) gives

1 + tan²(θ) = 1/cos²(θ)

We know cos(θ) is negative, so solve for cos²(θ) and take the negative square root.

cos²(θ) = 1/(1 + tan²(θ))

cos(θ) = - 1/√[1 + tan²(θ)]

Plug in tan(θ) = - 12/5 and solve for cos(θ) :

cos(θ) = - 1/√[1 + (-12/5)²] = - 5/13

Finally, solve for sin(θ/2) and tan(θ/2) :

sin(θ/2) = √[(1 - (- 5/13)) / 2] = 3/√(13)

tan(θ/2) = √[(1 - (- 5/13)) / (1 + (- 5/13))] = 3/2

3 0

2 years ago

A can in the shape of a right cylinder is filled with 10W-40 oil. The weight of 10W-40 oil is 0.857 gram per cubic centimeter. I

Leya [2.2K]

To solve this, we have to find the volume of the cylinder first. The formula to be used is $V = \pi r^{2} h$

Given:V= ?r= 6cmh= 10cm
Solution: $V = \pi r^{2} h$
V= (3.14)(6cm) $^{2}$ x 10cmV= (3.14)( $36cm^{2}$ ) x 10cmV= ( $113.04cm^{2}$ ) x 10cmV= 1130.4cm^3
Finding the volume of the cylinder, we can now solve what the weight of the oil is. Using the formula of density, Density = mass/volume, we can derive a formula to get the weight.
Given:Density = 0.857 gm/cm^3Volume = 1130.4 cm^3
Solution:weight = density x volumew= (0.857 gm/cm^3) (1130.4cm^3)w= 968.7528 gm
The weight of the oil is 968.75 gm.

5 0

3 years ago

Help me this assignment is due soon.

AlekseyPX

So maybe it’s 5, it’s equivalent to the side with 6, just shorter

6 0

3 years ago