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Pavel [41]
2 years ago
10

What volume of 15.9 M Nitric acid would be required to make 7.2 L of 6.00 M nitric acid? (hint: dilution problem) will mark brai

nliest if correct
a. 2.72 L
b. 686.88 L
c. .075 L
d. 272
Chemistry
1 answer:
irakobra [83]2 years ago
8 0

Answer:

d

Explanation:

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How much NH4Cl can you dissolve in 200 g of water at 90° to make a saturated solution?

C) 140

8 0
3 years ago
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Whag is the answer. please i need help​
icang [17]

Answer:

First option

Explanation:

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5 0
3 years ago
Briefly explain why the bulk temperature of the water remains low (at room temperature)
elena55 [62]
If the humidity of the room is low, the water that contacts the air directly could evaporate and takes some energy from the bulk thus decreasing its temperature steadily. This allows the water to have a lower temperature.
4 0
3 years ago
Is it possible to prove that something is real or true of you can’t directly observe it? If no, why not? If yes, how would you d
dangina [55]

Answer:

I don't know if you can directly prove it with evidence if you haven't observed it but you can maybe take an educated guess by the aftermath of it?

For example, you see a burnt log. At this time, people don't know what fire is. After we study the log, we could see that it takes extreme temperature in order to burn the log and that would help people see that there is a force like fire that can cause this. In a way, finding out that extreme temperatures burns stuff is another step closer to the discovery and proof of fire

I hope that makes sense

4 0
2 years ago
What is the radius of a hydrogen atom whose electron is bound by 0.544 ev? express your answer with the appropriate units?
insens350 [35]
First, we need to calculate the principal quantum number n for this electron, using the equation:
E = (-13.60 eV) / (n x n)
where E is the energy that is used to bound the electron (here, E = - 0.544 eV).
- 0.544 eV = (-13.60 eV) / (n x n)
n x n = (- 13.60 eV) / (- 0.544 eV)
n x n = 25
n = 5

The orbital radius that is equal to the radius of a hydrogen atom is calculated using the equation:
r = 0.053 nm x n x n
r = 0.053 nm x 5 x 5
r = 0.053 nm x 25
r = 1.325 nm
6 0
3 years ago
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