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dybincka [34]
3 years ago
10

Two cars initially at rest on a frictionless surface are blown apart by an explosion. The one with twice the mass ends up moving

to the right at 10 meters/second. The less massive car ends up moving to the left at what speed
Physics
1 answer:
DENIUS [597]3 years ago
6 0

Answer:

v = 20 m/s

Explanation:

Given that :

Initial Velocity of cars (u) = 0

Car with smaller mass = m

Car with larger mass = 2m

Final velocity of smaller mass = v

Final velocity of larger mass v2 = 10

Using the relation :

Initial momentum = final momentum

m1u1 + m2u2 = m1v1 + m2v2

Since u = 0

m1v1 + m2v2 = 0

mv + 2m * 10 = 0

mv + 20m = 0

mv = 20m

v = 20m / m

v = 20

Final velocity of larger mass car will be 20 m/s

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Answer:

Kr = 0.7618K

Explanation:

Suppose that the object's velocity is V, then his kinetic energy is:

K = \frac{mv^{2} }{2}

K = \frac{(16)v^{2} }{2}

K = 8v^{2}

The rotational kinetic energy is

Kr = \frac{Iw^{2} }{2}

           where I: The moment of inertia

                      ω: angular velocity

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Kr = 0.295w^{2}

How the movement is without slipping, then  

ω = \frac{v}{r}

ω = \frac{v}{0.22}

Thus

Kr = \frac{0.295v^{2} }{0.22^{2} }

Kr = 6.095v^{2}

8v^{2}  ---->  1

6.095v^{2}----->?

Kr = 0.7618K

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4 years ago
Lithium has an atomic number of 3. How many electrons does it have?
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Answer:

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4 0
3 years ago
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A 5.0kg toolbox is raised from the ground by a rope. If the upward acceleration of the bucket is 2.5 m/s^2, find the force exert
swat32

Answer:

62 N

Explanation:

Sum of the forces on the toolbox:

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T − mg = ma

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