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dedylja [7]
3 years ago
11

The Bugatti Veyron requires 2.40 s to accelerate from 0 to 60.0 mi/h. Calculate the distance that the car would travel in the ti

me it takes to reach 90.0 km/h, which is the speed limit on many Canadian roads. Compare your answer to the distance that the Saleen S7 Twin Turbo would travel while accelerating to the same final speed (The Saleen S7 Twin Turbo requires 2.8 s to accelerate from 0 to 60.0 mi/h).

Physics
1 answer:
kipiarov [429]3 years ago
6 0

Answer:

Δx for Bugatti = 27.9m

Δx for Saleen = 32.6m

Explanation:

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The magnetic field at the equator points north. If you throw a positively charged object (for example, a baseball with some elec
PilotLPTM [1.2K]

Answer:

The magnetic force points in the positive z-direction, which corresponds to the upward direction.

Option 2 is correct, the force points in the upwards direction.

Explanation:

The magnetic force on any charge is given as the cross product of qv and B

F = qv × B

where q = charge on the ball thrown = +q (Since it is positively charged)

v = velocity of the charged ball = (+vî) (velocity is in the eastern direction)

B = Magnetic field = (+Bj) (Magnetic field is in the northern direction; pointing forward)

F = qv × B = (+qvî) × (Bj)

F =

| î j k |

| qv 0 0|

| 0 B 0

F = i(0 - 0) - j(0 - 0) + k(qvB - 0)

F = (qvB)k N

The force is in the z-direction.

We could also use the right hand rule; if we point the index finger east (direction of the velocity), the middle finger northwards (direction of the magnetic field), the thumb points in the upward direction (direction of the magnetic force). Hence, the magnetic force is acting upwards, in the positive z-direction too.

Hope this Helps!!!

5 0
3 years ago
Bob and Lily are riding on a typical carousel. Bob rides on a horse near the outer edge of the circular platform, and Lily rides
alukav5142 [94]

Answer:

Bob's angular speed is the same as that of lily

Explanation:

Because for a carousel the angular speed remains the same since velocity at center and edge are the same

6 0
4 years ago
The sound from a loud speaker has an intensity level of 80 db at a distance of 2.0m. Consider the speaker to be a point source,
Tamiku [17]

Answer:

2.83m

Explanation:

The information that we have is

Intensity at 2.0 m: I=80dB and r_{1}=2m

we need an intensity level of: I_{2}=40dB

thus, we are looking for the distance r_{2}.

which we can find with the law for intensity and distance:

(\frac{r_{2}}{r_{1}} )^2=\frac{I_{1}}{I_{2}}

we solve for r_{2}:

\frac{r_{2}}{r_{1}}=\sqrt{\frac{I_{1}}{I_{2}} }\\\\r_{2}=r_{1}\sqrt{\frac{I_{1}}{I_{2}} }

and we substitute the known values:

r_{2}=(2m)\sqrt{\frac{80dB}{40dB} }\\\\r_{2}=(2m)\sqrt{2}\\ r_{2}=2.83m

at a distance of 2.83m the intensity level is 40dB

5 0
3 years ago
Heat is transferred in a gas through _____.
tangare [24]
The answer would be conduction. hope that helped
3 0
3 years ago
Read 2 more answers
earth orbits the sun once every 365.25 days. Find the average angular. speed of Earth about the sun.Answer in units of rad/s.
anzhelika [568]

Answer:

1.99\cdot 10^{-7} rad/s

Explanation:

The average angular speed of the Earth about the Sun is given by:

\omega = \frac{2 \pi}{T}

where

2 \pi rad is the total angle corresponding to one revolution of the Earth around the Sun

T is the orbital period of the Earth

The orbital period of the Earth is 365.25 d. We must convert it into seconds first:

T=365.25 d \cdot (24 h/d) \cdot (60 min/h) \cdot (60 s/min)=3.16\cdot 10^7 s

And by substituting into the equation above, we find the average angular speed:

\omega=\frac{2 \pi rad}{3.16\cdot 10^7 m/s}=1.99\cdot 10^{-7} rad/s

7 0
3 years ago
Read 2 more answers
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