All categories

3 years ago

What would be the wavelength of light that has a frequency of 3 X 10-4 Hz in a vacuum?

Chemistry

1 answer:

ziro4ka [17]3 years ago

6 0

Answer:

$\lambda=10^{12}\ m$

Explanation:

Given that,

The frequency of the light, $f=3\times 10^{-4}\ Hz$

We need to find the wavelength of the light.

The relation between frequency, wavelength and the speed of light is given by :

$c=f\lambda\\\\\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{3\times 10^{-4}}\\\\\lambda=10^{12}\ m$

So, the wavelength of the light is $10^{12}\ m$ .

You might be interested in

What is the final temperature of the metal

Natasha_Volkova [10]

Answer:

There is no exact answer for this question tbh.

6 0

3 years ago

7) Sodium is much more apt to exist as a cation than chlorine because: a) chlorine is a gas and sodium is a solid b) chlorine ha

sleet_krkn [62]

Answer:

Option (d) chlorine has a greater ionization energy than sodium

Explanation:

Ionization energy is the energy required to remove an electron from a gaseous atom or ion. Sodium has just 1 electron in it's outmost shell and chlorine has 7.

Sodium needs 7 electrons to complete it's octet configuration and chlorine needs just 1.

Sodium can not attract 7 electrons to complete it's octet configuration instead it will easily lose the 1 electron in it's outmost shell to form cation. On the other hand, it will be difficult for chlorine to lose any of it's outmost electrons. This makes chlorine to have higher ionization energy than sodium.

6 0

3 years ago

3Al + 3NH4ClO4 → Al2O3 + AlCl3 + 3NO + 6H2O How many moles of AlCl3 are produced?

zhuklara [117]

Answer: 1 mol of $AlCl_3$ will be produced from this reaction.

Explanation: Reaction follows,

$3Al+3NH_4ClO_4\rightarrow Al_2O_3+AlCl_3+3NO+6H_2Oc$

As seen from the balanced chemical equation above, we get

For every 3 moles of Aluminium and 3 moles of $NH_4ClO_4$ , 1 mole of $Al_2O_3$ is formed.

For every 3 moles of Aluminium and 3 moles of $NH_4ClO_4$ , 1 mole of $AlCl_3$ is formed.

For every 3 moles of Aluminium and 3 moles of $NH_4ClO_4$ , 3 moles of $NO$ is formed.

For every 3 moles of Aluminium and 3 moles of $NH_4ClO_4$ , 6 moles of $H_2O$ is formed.

7 0

4 years ago

Read 3 more answers

What mass of nitrogen is needed to fill an 855 L tank at STP?

scoundrel [369]

Answer:

It takes 1,068.76 grams of nitrogen to fill an 855 L tank at STP.

Explanation:

The STP conditions refer to the standard temperature and pressure. Pressure values at 1 atmosphere and temperature at 0 ° C or 273.15 °K are used and are reference values for gases.

On the other side, the pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:

P*V = n*R*T

where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas.

So, in this case:

P= 1 atm
V= 855 L
n= ?
R= 0.082 $\frac{atm*L}{mol*K}$
T= 273.15 K

Replacing:

1 atm* 855 L= n* 0.082 $\frac{atm*L}{mol*K}$ * 273.15 K

Solving:

$n=\frac{1 atm* 855 L}{0.082\frac{atm*L}{mol*K} *273.15 K }$

n= 38.17 moles

Being the molar mass of nitrogen N2 equal to 28 g / mol, you can apply the following rule of three: if there are 28 grams in 1 mole, how much mass is there in 38.17 moles?

$mass=\frac{38.17 moles*28 grams}{1 mole}$

mass= 1,068.76 grams

It takes 1,068.76 grams of nitrogen to fill an 855 L tank at STP.

3 0

4 years ago

125 ml of nitrogen gas is collected at 70.0 degrees Celsius. The pressure

dybincka [34]

Answer: Volume of the gas at STP is 22.53 L.

Explanation:

Given : Volume = 125 mL (as 1 mL = 0.001 L) = 0.125 L

Temperature = $70^{o}C = (70 + 273) K = 343 K$

Pressure = $125 kPa = 125 kPa \times \frac{0.01 atm}{1 kPa} = 1.25 atm$

According to the ideal gas equation, the volume of given nitrogen gas is calculated as follows.

PV = nRT

where,

P = pressure

V = volume

n = number of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into above formula as follows.

$1.25 atm \times V = 1 mol \times 0.0821 L atm/mol K \times 343 K\\V = \frac{1 mol \times 0.0821 L atm/mol K \times 343 K}{1.25 atm}\\= \frac{28.1603}{1.25} L\\= 22.53 L$

Hence, volume of the gas at STP is 22.53 L.

5 0

3 years ago