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tangare [24]
3 years ago
10

Calculate the standard potential for the following galvanic cell: Fe(s) | Fe2+(aq) || Ag+(aq) | Ag(s) which has the overall bala

nced equation: Fe(s)+2Ag+(aq)→Fe2+(aq)+2Ag(s) Express your answer to three significant figures and include the appropriate units. View Available Hint(s)
Chemistry
1 answer:
Nataly [62]3 years ago
6 0

Answer:

E° = 1.24 V

Explanation:

Let's consider the following galvanic cell: Fe(s) | Fe²⁺(aq) || Ag⁺(aq) | Ag(s)

According to this notation, Fe is in the anode (where oxidation occurs) and Ag is in the cathode (where reduction occurs). The corresponding half-reactions are:

Anode: Fe(s) ⇒ Fe²⁺(aq) + 2 e⁻

Cathode: Ag⁺(aq) + 1 e⁻ ⇒ Ag(s)

The standard cell potential (E°) is the difference between the standard reduction potential of the cathode and the standard reduction potential of the anode.

E° = E°red, cat - E°red, an

E° = 0.80 V - (-0.44 V) = 1.24 V

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1) The element that will most likely lose electrons to form positive ions when bonding with other elements is rubidium (Rb).

2) The correct statement about sodium atoms is; "The sodium atom transfers electrons to the chlorine atoms to form ionic bonds."

3) Based on their location in the periodic table, nitrogen (N) and oxygen (O) are most likely to form covalent bonds with each other

4) Electronegativity is best described by the phrase; "the relative strength with which an element attracts electrons in a chemical bond"

Metals of group 1 and 2 are highly electropositive and are more likely to loose electrons in a bonding situation. Therefore, the element that will most likely lose electrons to form positive ions when bonding with other elements is rubidium (Rb).

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According to Linus Pauling, electronegativity refers to the ability of an element in a compound to draw electrons towards itself.

Learn more: brainly.com/question/14077687

8 0
3 years ago
What was the control in Pasteur's experiment?
Sholpan [36]

Answer:

a straight neck flask to allow air to get in

Explanation:

I took the test eWe

8 0
4 years ago
P is the pressure in atmospheres (atm), V is the volume in liters (L), n is the number of moles, R is the gas constant (0.0821 L
yKpoI14uk [10]

Answer:

The mass of the neon gas  m = 1.214 kg

Explanation:

Pressure = 3 atm = 304 k pa

Volume = 0.57 L = 0.00057 m^{3}

Temperature = 75 °c = 348 K

Universal gas constant = 0.0821 \frac{L . atm}{mol K}

We have to change the unit of this constant. it may be written as

Universal gas constant = 8.314 \frac{KJ}{mol K}

Gas constant for neon = \frac{8.314}{20} = 0.41 \frac{KJ}{kg K}

From ideal gas equation,

P V = m R T ------- (1)

We have all the variables except m. so we have to solve this equation for mass (m).

⇒ 304 × 10^{3} × 0.00057 = m × 0.41 × 348

⇒ 173.28 = 142.68 × m

⇒ m = 1.214 kg

This is the mass of the neon gas.

4 0
3 years ago
What is the balanced equation for H3PO4=H4P2O7+H2O
podryga [215]

Answer:

2H3PO4=H4P2O7+H2O

Explanation:

2H3PO4=H4P2O7+H2O

5 0
3 years ago
Are diamonds flammable?
Debora [2.8K]
A match-head is flammable, but you have to get it up to its ignition temperature first.

A diamond is flammable, but its ignition temperature is astronomical and
totally out of sight.
4 0
3 years ago
Read 2 more answers
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