All atoms of a given element must contain the same number of

How much cooking liquid is needed when employing the pasta method?

Sonbull [250]

A l l of IT? idk im 7

8 0

3 years ago

The particles of a substances are arranged in a definite geometric pattern and are constantly vibrating. This substances can be

WINSTONCH [101]

Answer:easy

Explanation: the answer is '/.'/;==-.'/'.;.;pand'.[;';; because,/.;'[][]';;/..,./. hope it helps )

3 0

3 years ago

Sometimes a new product is test-marketed. A limited amount of the product is released to a select group of users. Then the group

Akimi4 [234]

Answer:

Modification Step

Explanation:

The entire reason why test-marketing exists is to make sure that the product will be well received by the public. Once the test marketing concludes, the data from the test is analyzed. Then the company decides whether or not they will make changes on how the product looks, feels, performs, or even rebranding the product, all to make sure that the final consumer will like the product enough to want to purchase and continuously use the product. Which will in term increase profits for the company.

5 0

2 years ago

If the enantiomeric excess of a mixture is 75%, what are the % compositions of the major and minor enantiomer?

Maru [420]

Let us say that R is the major enantiomer, while S is the minor enantiomer, therefore the formula for enantiomeric excess (ee) is:

ee = (R – S) * 100%

Let us further say that the fraction of R is x (R = x), and therefore fraction of S is 1 – x (S = 1 – x), therefore:

75 = (x – (1 – x)) * 100

75 = 100 x – 100 + 100 x

200 x = 175

x = 0.875

Summary of answers:

R = major enantiomer = 0.875 or 87.5%

<span>S = minor enantiomer = (1 – 0.875) = 0.125 or 12.5%</span>

7 0

3 years ago

Consider the reaction 5 Br− (aq) + BrO3− (aq) + 6 H+ (aq) → 3 Br2 (aq) + 3 H2O (l) The average rate of consumption of Br− is 1.8

kaheart [24]

Answer : The average rate of consumption of $H^+$ during the same time interval is, 2.17 M/s

Explanation :

The general rate of reaction is,

$aA+bB\rightarrow cC+dD$

Rate of reaction : It is defined as the change in the concentration of any one of the reactants or products per unit time.

The expression for rate of reaction will be :

$\text{Rate of disappearance of A}=-\frac{1}{a}\frac{d[A]}{dt}$

$\text{Rate of disappearance of B}=-\frac{1}{b}\frac{d[B]}{dt}$

$\text{Rate of formation of C}=+\frac{1}{c}\frac{d[C]}{dt}$

$\text{Rate of formation of D}=+\frac{1}{d}\frac{d[D]}{dt}$

$Rate=-\frac{1}{a}\frac{d[A]}{dt}=-\frac{1}{b}\frac{d[B]}{dt}=+\frac{1}{c}\frac{d[C]}{dt}=+\frac{1}{d}\frac{d[D]}{dt}$

From this we conclude that,

In the rate of reaction, A and B are the reactants and C and D are the products.

a, b, c and d are the stoichiometric coefficient of A, B, C and D respectively.

The negative sign along with the reactant terms is used simply to show that the concentration of the reactant is decreasing and positive sign along with the product terms is used simply to show that the concentration of the product is increasing.

The given rate of reaction is,

$5Br^-(aq)+BrO_3^-(aq)+6H^+(aq)\rightarrow 3Br_2(aq)+3H_2O(l)$