Answer:
C
Step-by-step explanation:
The sequence is arithmetic with n th term
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = 1 and d = 3, thus
= 1 + 3(n - 1) = 1 + 3n - 3 = 3n - 2 → C
5=4x+2x-7
5+7=6x
12=6x
12/6=6x/6
2=x
Answer: C
Step-by-step explanation:
If we know the value of the car decreases $500 for every 1,000 miles, and that the car is driven about 10,000 miles every year, that means that you need to take the total value of the car (23,000) and subtract it from the amount of money it is losing per year. Again, the car is driven about 10,000 miles per year, so that means that the car will most likely continue to be driven 10,000 miles per year. If you do the math, for one year, the value of the car will drop $5,000 ($500 x 10, because it is $500 per every 1,000 miles) So, for each year, you can just multiply the number of years by $5,000 to find out how much the vehicle has depreciated over time.
Hope this helped you and made sense! Feel free to ask me any questions you have!
The right answer is not among those offered. The domain is
.. {-9, -6, 4, 7}
___
The 4th selection {4, 7} is the best of those offered, but it is not correct.
<h3>
Answer: 3 m/s^2</h3>
=======================================================
According to Newton's Second Law, we know that
F = m*a
where F is the force applied, m is the mass and 'a' is the acceleration.
We see that this is a direct variation equation for F and a, such that m is the constant of variation. It's similar to how y = kx is also a direct variation equation.
Plug in F = 35 and a = 5 to find m
F = ma
35 = m*5
35/5 = m
7 = m
m = 7
The object has a mass of 7 kg
Our equation F = ma updates to F = 7a
Now plug in the force F = 21 to find 'a'
F = 7a
21 = 7a
21/7 = a
3 = a
a = 3
The acceleration will be 3 m/s^2
Notice how a smaller force applied means that the acceleration has also gone down as well.
