All categories

3 years ago

Given that is directly proportional to (p-1)2 and p is always positive, find the

Mathematics

1 answer:

Arturiano [62]3 years ago

4 0

Answer:

p = 10.8

Step-by-step explanation:

Given that p is directly proportional to (p-1)² and p is always positive, then;

q = k (p-1)²

If q = 30 and p = 7

30 = k(7-1)²

30 = 6²k

30 = 36k

5 = 6k

k = 5/6

To get p when q = 80

q =k (p-1)²

80 = 5/6((p-1)²

480 = 5(p-1)²

480/5 = (p-1)²

(p-1)² = 96

p-1 = √96

p-1 = 9.8

p = 9.8 + 1

p = 10.8

B) 6

Ch 10.82

You might be interested in

Choose the equation below that represents the line passing through the point (−2, −3) with a slope of −6.

lubasha [3.4K]

Y = mx + b
slope(m) = -6
(-2,-3)...x = -2 and y = -3
now we sub....we r looking for b, the y int
-3 = -6(-2) + b
-3 = 12 + b
-3-12 = b
-15 = b

so ur equation is : y = -6x - 15

7 0

3 years ago

How to tell if an equation is linear or nonlinear?

gogolik [260]

A linear equation will contain a term in x has the highest degree. For example y = 2x - 5 . A non linear will contain terms with exponents 2 or higher
eg x^2 - 2x - 5 is nonlinear.

6 0

3 years ago

The surface area of the cube is 54 square feet. What is the length, in feet, of one edge of the cube?

Brut [27]

Answer:

3 ft

Step-by-step explanation:

A cube is made of 6 equal faces each of which is a square with the same side length. The surface area of the cube is the surface area of one side multiplied by 6. We know the surface area is 54 so divide this by 6.

54/6 = 9 ft^2

Since the surface must be a square, take the square root of 9 which is 3 ft. The length of one edge of the cube is 3 ft.

5 0

3 years ago

Find the least common multiple (LCM) of 8y^6+ 144y^5+ 640y^4 and 2y^4 + 40y^3 + 200y^2.

Mice21 [21]

Answer:

LCM = $8y^{4}(y+ 10)^{2}(y + 8)$

Step-by-step explanation:

Making factors of $8y^{6}+ 144y^{5}+ 640y^{4}$

Taking $8y^{4}$ common:

$\Rightarrow 8y^{4} (y^{2}+ 18y+ 80)$

Using factorization method:

$\Rightarrow 8y^{4} (y^{2}+ 10y + 8y + 80)\\\Rightarrow 8y^{4} (y (y+ 10) + 8(y + 10))\\\Rightarrow 8y^{4} (y+ 10)(y + 8))\\\Rightarrow \underline{2y^{2}} \times 4y^{2} \underline{(y+ 10)}(y + 8)) ..... (1)$

Now, Making factors of $2y^{4} + 40y^{3} + 200y^{2}$

Taking $2y^{2}$ common:

$\Rightarrow 2y^{2} (y^{2}+ 20y+ 100)$

Using factorization method:

$\Rightarrow 2y^{2} (y^{2}+ 10y+ 10y+ 100)\\\Rightarrow 2y^{2} (y (y+ 10) + 10(y + 10))\\\Rightarrow \underline {2y^{2} (y+ 10)}(y + 10) ............ (2)$

The underlined parts show the Highest Common Factor(HCF).

i.e. HCF is $2y^{2} (y+ 10)$ .

We know the relation between LCM, HCF of the two numbers 'p' , 'q' and the numbers themselves as:

$HCF \times LCM = p \times q$

Using equations (1) and (2): $\Rightarrow 2y^{2} (y+ 10) \times LCM = 2y^{2} \times 4y^{2}(y+ 10)(y + 8) \times 2y^{2} (y+ 10)(y + 10)\\\Rightarrow LCM = 2y^{2} \times 4y^{2}(y+ 10)(y + 8) \times (y + 10)\\\Rightarrow LCM = 8y^{4}(y+ 10)^{2}(y + 8)$

Hence, LCM = $8y^{4}(y+ 10)^{2}(y + 8)$

5 0

3 years ago

Simplify the expression: (2p + 1)(2) =

Oxana [17]

Answer:

4p +2

Step-by-step explanation:

(2p + 1)(2)

Distribute

2p * 2 + 1*2

4p +2

5 0

3 years ago

Read 2 more answers