Answer:
1.1, -5
Step-by-step explanation:
53 - 9y = 1
from equation i
53-9y = 1
-9y= 1-53 = -52
y = -52/-9= 52/9 = 5⁷/₉
-7.2 + 2y = -5
add 7.2 to both sides
2y= -5+7.2 = 2.2
y= 2.2/2 = 1.1
The value of z-score for a score that is three standard deviations above the mean is 3.
In this question,
A z-score measures exactly how many standard deviations a data point is above or below the mean. It allows us to calculate the probability of a score occurring within our normal distribution and enables us to compare two scores that are from different normal distributions.
Let x be the score
let μ be the mean and
let σ be the standard deviations
Now, x = μ + 3σ
The formula of z-score is

⇒ 
⇒ 
⇒ 
Hence we can conclude that the value of z-score for a score that is three standard deviations above the mean is 3.
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The two limits when x tends to zero are:

<h3 /><h3>How to get the limits when x tends to zero?</h3>
Notice that we have a jump at x = 0.
Then we can take two limits, one going from the negative side (where we will go along the blue line)
And other from the positive side (where we go along the orange line).
We will get:

Notice that the two limits are different, that means that the function is not a continuous function.
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