All categories

2 years ago

How much does it cost to operate a 90 W light bulb for one day if the cost per kilowatt-hour is $0.08

Physics

1 answer:

horrorfan [7]2 years ago

7 0

Answer:

$ 0.17

Explanation:

From the question given above, the following data were obtained:

Power (P) = 90 Watts

Time (t) = 1 day

Cost per KWh = $ 0.08

Cost of operation =?

Next, we shall convert 90 W to KW. This can be obtained as follow:

1000 W = 1 KW

Therefore,

90 W = 90 W × 1 KW / 1000 W

90 W = 0.09 KW

Next, we shall express 1 day in hour. This is shown below:

1 day = 24 hours

Next, we shall determine the energy consumption. This can be obtained as follow:

Power (P) = 0.09 KW

Time (t) = 24 h

Energy (E) =?

E = Pt

E = 0.09 × 24

E = 2.16 KWh

Finally, we shall determine the cost of operation. This can be obtained as follow:

Energy (E) = 2.16 KWh

Cost per KWh = $ 0.08

Cost of operation =?

Cost of operation = Energy × Cost per KWh

Cost of operation = 2.16 × 0.08

Cost of operation = $ 0.17

Thus, the cost of operating the light bulb for one day is $ 0.17

You might be interested in

A 15.0 Ohms resistor is connected in series to a 120V generator and two 10.0 Ohms resistors that are connected in parallel to ea

Nostrana [21]

Hi there! :)

Reference the diagram below for clarification.

We must begin by knowing the following rules for resistors in series and parallel.

In series:
$R_T = R_1 + R_2 + ... + R_n$

In parallel:
$\frac{1}{R_T} = \frac{1}{R_1} + \frac{1}{R_2} + ... + \frac{1}{R_n}$

We can begin solving for the equivalent resistance of the two resistors in parallel using the parallel rules.

$\frac{1}{R_{T, parallel}} = \frac{1}{10} + \frac{1}{10}\\\\\frac{1}{R_{T, parallel}} = \frac{2}{10} = \frac{1}{5}\\\\R_{T, parallel} = 5\Omega$

Now that we have reduced the parallel resistors to a 'single' resistor, we can add their equivalent resistance with the other resistor in parallel (15 Ohm) using series rules:
$R_T = 15 + 5\\\\\boxed{R_T = 20 \Omega}$

We can use Ohm's law to solve for the current in the circuit.

$i = \frac{V}{R_T}\\\\i = \frac{120}{20} = \boxed{6 A}$

For resistors in series, both resistors receive the SAME current.

Therefore, the 15Ω resistor receives 6A, and the parallel COMBO (not each individual resistor, but the 5Ω equivalent when combined) receives 6A.

In this instance, since both of the resistors in parallel are equal, the current is SPLIT EQUALLY between the two. (Current in parallel ADDS UP). Therefore, an even split between 2 resistors of 6 A is <u>3A for each 10Ω resistor</u>.

Since the 15.0 Ω resistor receives 6A, we can use Ohm's Law to solve for voltage.

$V = iR\\\\V = (6)(15) = \boxed{90 V}$

4 0

1 year ago

1. Calcula la fuerza de atracción electrostática entre dos cuerpos de cargas q1 = -18 C y q2 = +5 mC, separados entre sí por una

romanna [79]

Answer:

A) F=-20.16×10⁹N

B) if the distance doubles, force is 4 times smaller.

Explanation:

q1=-28C

q2=5mC=0.005C

d=25cm=0.25m

Electrostatic force between charges: F=k×q1×q2/d², where k is a coefficient that has the value k=9 × 10⁹ N⋅m²⋅C^(-2) for air.

Thus:

F=9×10⁹×(-28)×0.005/0.25²

F=-20.16×10⁹N

The minus sign indicates attraction.

If distance doubles, d1=2×d, then we have 4d² at the denominator and the force is 4 times smaller.

6 0

3 years ago

When light generated by a lamp in a light microscope passes into a lens, the speed of the light _______ because the glass lens h

Alina [70]

Answer:

the answer is slows and greater

Hopes it helps!

6 0

3 years ago

a pendulum, 2.0 m in length, is released with a push when the string is at an angle of 25 o from the vertical. if the initial sp

stiks02 [169]

Answer:

1 / 2 m v^2 = L m g (1 - cos θ)

This is the KE due to the pendulum falling from a 25 deg displacement

v^2 = 2 L g (1 - cos 25) = 2 * 2 * 9.8 (1 - .906) = 3.67 m^2/s^2

v = 1.92 m/s this is the speed due to an initial displacement of 25 deg

Its speed at the bottom would then be

1.92 + 1.2 = 3.12 m/s since it gains 1.92 m/s from its initial displacement

3 0

1 year ago

Suppose that a person has an average heart rate of 72.0 beats/min. How many beats does he or she have in 2.0 y? In 2.00 y? In 2.

Alex17521 [72]

2.0y i think this is guess but if it right then thats good

3 0

3 years ago