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____ [38]
3 years ago
9

A sheet of aluminum (al) foil has a total area of 1.000 ft2 and a mass of 3.716 g. what is the thickness of the foil in millimet

ers (density of al = 2.699 g/cm3)?
Physics
1 answer:
Andrews [41]3 years ago
3 0
The mass of the sheet of aluminium is the product between its density d and its volume V:
m=dV
Re-arranging the equation, we can find the volume of the sheet:
V= \frac{m}{d}= \frac{3.716 g}{2.699 g/cm^3}=  1.377 cm^3

Converted in millimeters,
V=1377 mm^3

The area is 
A=1.00 ft^2
Since 1 ft = 0.305 m, this area corresponds to
A=1.00 ft^2 = (0.305 m)^2 = 0.093 m^2 = 0.093 \cdot 10^6 mm^2

So we can now find the thickness of the sheet of aluminium:
t= \frac{V}{A}= \frac{1377 mm^2}{0.093 \cdot 10^6 mm^2}=0.015 mm
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The velocity of the target and arrow after collision is 6.67m/s

<u>Explanation:</u>

Given:

Mass of arrow, mₐ = 415g

Speed of arrow, vₐ = 68.5m/s

Mass of the target, mₓ = 3.3kg = 3300g

speed of the target, vₓ = -1.1m/s (Because the target moves in opposite direction

Velocity of the target and arrow after collision, vₙ = ?

Applying the conservation of momentum,

mₐvₐ + mₓvₓ = (mₐ+mₓ) vₙ

415 X 68.5 + 3300 X -1.1 = (415+3300) X vₙ

28427.5 - 3630 = 3715 X vₙ

24797.5 = 3715 X vₙ

vₙ = 6.67m/s

Therefore, the velocity of the target and arrow after collision is 6.67m/s

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3 years ago
Hydrogen is a nonmetal with many nonmetal properties. Why is it on the periodic table with the metals in Group 1?
mrs_skeptik [129]

Answer:

This is because it has ns1 electron configuration like the alkali metals.

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6 0
2 years ago
Sam is observing the velocity of a car at different times. After two hours, the velocity of the car is 50 km/h. After six hours,
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A )
t 1 = 2 h,  t 2 = 6 h
Δ t = t 2 - t 1 = 6 - 2 = 4 h
54 = 50 + a Δ t
54 = 50 + 4 a
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An equation that can be used to describe the velocity of the car at the different times is:
v = 48 + t
B ) The graph is in the attachment. 
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3 years ago
A student jobs around a square park two times. Starting and ending at the gate to the park. The square jogging track is 40 meter
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The answer would be the first one
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An object with a mass of 10 kg is accelerated upward at 2 m/sec2. What force is required?
telo118 [61]

Answer:

Answer: Given m = 10 kg and . F = 20 N. Thus, the force required to accelerate the object upward direction is 20 N.

Explanation:

Answer: Given m = 10 kg and . F = 20 N. Thus, the force required to accelerate the object upward direction is 20 N.

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2 years ago
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