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vovangra [49]
3 years ago
10

in last weeks volleyball game Ashley served 15 times and made 2 errors. What was her serving percentage? (what percent did she s

erve it in?
Mathematics
1 answer:
Setler79 [48]3 years ago
7 0
1300%


hope this helps
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Help pls math ppl<br> Thank
Marianna [84]

Answer: you are correct

Step-by-step explanation:

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You want to limit the amount of television you watch to an average of at most 2 hours per week during an 8-week period. How many
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You have been given the information
2 hour per week
8 week period
So, to find out how many hours of television you can watch, multiply 8 by 2 = 16 hours of television in a 8 week period.
Hope this helps!!
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Emily has a bag of 20 fruit flavoured sweets 7 of the sweets are strawberry flavoured 11 are lime flavour and two are lemon flav
Fantom [35]

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IT IS BECAUSE THERE IS NO ORANGE FLAVOURED SWEET.

= 0/20 = 0

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3 years ago
If you deposit $300 in an account with a 6% interest rate, how much will be in your account after 1 year?
Ivahew [28]
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3 years ago
Suppose a random sample of 100 observations from a binomial population gives a value of pˆ = .63 and you wish to test the null h
irakobra [83]

Answer:

We conclude that the population proportion is equal to 0.70.

Step-by-step explanation:

We are given that a random sample of 100 observations from a binomial population gives a value of pˆ = 0.63 and you wish to test the null hypothesis that the population parameter p is equal to 0.70 against the alternative hypothesis that p is less than 0.70.

Let p = <u><em>population proportion.</em></u>

(1) The intuition tells us that the population parameter p may be less than 0.70 as the sample proportion comes out to be less than 0.70 and also the sample is large enough.

(2) So, Null Hypothesis, H_0 : p = 0.70      {means that the population proportion is equal to 0.70}

Alternate Hypothesis, H_A : p < 0.70      {means that the population proportion is less than 0.70}

The test statistics that would be used here <u>One-sample z-test</u> for proportions;

                           T.S. =  \frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }  ~  N(0,1)

where, \hat p = sample proportion = 0.63

            n = sample of observations = 100

So, <u><em>the test statistics</em></u>  =  \frac{0.63-0.70}{\sqrt{\frac{0.70(1-0.70)}{100} } }

                                     =  -1.528

The value of z-test statistics is -1.528.

<u>Now at 0.05 level of significance, the z table gives a critical value of -1.645 for the left-tailed test.</u>

Since our test statistics is more than the critical value of z as -1.528 > -1.645, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u><em>we fail to reject our null hypothesis</em></u>.

Therefore, we conclude that the population proportion is equal to 0.70.

(c) The observed level of significance in part B is 0.05 on the basis of which we find our critical value of z.

4 0
3 years ago
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