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3 years ago

Adding energy to an endothermic reaction will push the reaction towards...

Chemistry

1 answer:

Veronika [31]3 years ago

3 0

Answer:

Products

Explanation:

In an endothermic reaction, energy is taken in. This means that the absorption of energy favours the forward reaction.

Hence for a process; A + B----> C, if energy must be added for the equilibrium to shift towards the right and more of C is produced, then the reaction is endothermic.

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Inferring the strength of electrical forces

shtirl [24]

The strength of electrical forces tells about the size of charge on the object.

<h3>What is infer about the strength of electrical forces?</h3>

The strength of the electric force between two charged objects depends on the amount of charge that each object have and on the distance between the two charges. When the amount of charge gets bigger, the force also gets bigger, and when the distance between the two charges gets larger, the force also gets smaller. Electric forces are the attraction present between two charge bodies.

So we can conclude that The strength of electrical forces tells about the size of charge on the object.

Learn more about force here: brainly.com/question/12970081

#SPJ1

8 0

2 years ago

A gas is under a pressure of 760torr and occupies volume of 525cm3. If the pressure is doubled, what volume would gas now occupy

german

262. 5cm3.

using the Boyles law formula. p1v1=p2v2

P1=760torr.

v1=525cm³

p2=760×2=1520torr.

v2=?

p1v1=p2v2

760×525=1520×v2

v2=[ 760×525]÷1520

v2= 262.5cm³

when the pressure increases, the volume decreases.

5 0

3 years ago

The compound known as diethyl ether, commonly referred to as ether, contains carbon, hydrogen, and oxygen. A 1.751 g sample of e

fredd [130]

Answer: The empirical formula for the given compound is $C_{4}H_{10}O$

Explanation:

The chemical equation for the combustion of ether follows:

$C_xH_yO_z+O_2\rightarrow CO_2+H_2O$

where, 'x', 'y' and 'z' are the subscripts of carbon, hydrogen and oxygen respectively.

We are given:

Mass of $CO_2=4.159g$

Mass of $H_2O=2.128g$

Mass of sample = 1.751 g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 4.159 g of carbon dioxide, $\frac{12}{44}\times 4.159=1.134g$ of carbon will be contained.

For calculating the mass of hydrogen:

In 18 g of water, 2 g of hydrogen is contained.

So, in 2.128 g of water, $\frac{2}{18}\times 2.128=0.236g$ of hydrogen will be contained.

Mass of oxygen in the compound = (1.751) - (1.134 + 0.236) = 0.381 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{1.134g}{12g/mole}=0.0945moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.236g}{1g/mole}=0.236moles$

Moles of Oxygen = $\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{0.381g}{16g/mole}=0.0238moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.0238 moles.

For Carbon = $\frac{0.0945}{0.0238}=3.97\approx 4$

For Hydrogen = $\frac{0.236}{0.0238}=9.91\approx 10$

For Oxygen = $\frac{0.0238}{0.0238}=1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O = 4 : 10 : 1

Hence, the empirical formula for the given compound is $C_{4}H_{10}O$

7 0

3 years ago

The Michaelis–Menten equation is an expression of the relationship between the initial velocity ????0 of an enzymatic reaction a

inna [77]

Answer:

(2) Half of the active sites are occupied by substrate.

Explanation:

The Michaelis–Menten equation is the rate equation for a one-substrate enzyme-catalyzed reaction. It is an expression of the relationship between the initial velocity V₀ of an enzymatic reaction, the maximum velocity Vmax, and substrate concentration [S] which are all related through the Michaelis constant, Km.

Mathematically, the Michaelis–Menten equation is given as:

V₀ = Vmax[S]/Km + [S]

A special relationship exists between the Michaelis constant and substrate concentration when the enzyme is operating at half its maximum velocity, i.e. at V₀ = Vmax/2

substituting, Vmax/2 = V₀ in the Michaelis–Menten equation

Vmax/2 = Vmax[S]/Km + [S]

dividing through with Vmax

1/2 = [S]/Km + [S]

2[S] = Km + [S]

2[S] - [S] = Km

[S] = Km

Therefore, when the enzyme is operating at half its maximum velocity, i.e. when half of the active sites are occupied by substrate, [S] = Km

5 0

3 years ago

Identify all of the following three changes that would shift the equilibrium of the Haber [HAH-bur] process to the right: a) Add

Vladimir [108]

Answer:

a).Adding hydrogen gas : Forward direction

b) Adding an inert gas

At constant pressure : Backward direction
At constant Volume : No change

c) Increasing the volume of the container:Backward direction

Explanation:

According to Le-Chatelier's principle = Any disturbance is created in the equilibrium , it will shift the equilibrium in such a way to reduce disturbance.

This disturbance can be : Change in concentration , pressure, temperature , Addition of gas etc.

Temperature : when temperature is increased for endothermic reaction . The equilibrium shift in forward. For exothermic reaction , on increasing temperature ,equilibrium shift backward.

Pressure : On increasing pressure the equilibrium shifts towards less number of gaseous molecules.

Volume : Since volume varies inversely with pressure . It's effect is opposite to that produced by pressure change i.e On increasing Volume the equilibrium shifts towards more number of gaseous molecules.

On Addition of Inert gas : The equilibrium shift toward the side where more gaseous molecules are present.

Concentration : On increasing concentration , the equilibrium will shift such that the substance added get removed .

Haber Process :

$N_{2}(g)+3H_{2}(g)\rightarrow 2NH_{3}(g)$

This is exothermic reaction (H = negative)

Molecules of gases are more on left side(reactants) than right side(product)

a) Adding hydrogen gas :

According to Le-Chatelier's principle ,The equilibrium will shift in a direction where the Hydrogen gas is consumed (removed)

Hence Equilibrium shift in forward direction

b) Adding an inert gas : There are two situation

If inert gas is added at constant pressure: Total Volume is increased, so equilibrium will shift in direction where there is increase in number of molecule(Le-Chatelier's).Here, equilibrium shift in backward direction
If inert gas is added at constant Volume :No change in equilibrium.This because if inert gas is added pressure will increase but there is no change in moles per unit volume(constant) of gases.

c) Increasing the volume of the container:

If total Volume is increased, the number of molecules per unit volume decrease.In order to maintain the equilibrium constant , the equilibrium shift in direction where there is increase in number of molecule(Le-Chatelier's).

In this case Backward direction.

3 0

4 years ago