What volume will 2.0 moles of nitrogen occupy at .947 atm and 20° C ? ____ L
1 answer:
Answer:
The volume is 50, 74 liters
Explanation:
We use the formula PV = nRT. The temperature in Kelvin is = 273+ 20 =293K
PV=nRT ---> V = (nRT) / P
V= (2.0 mol x 0,082 l atm /K mol x 293 K) / 0,947 atm
V=50,74128828 l
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