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Mashutka [201]
3 years ago
5

There's a bag of 10 marbles. Three of them are red, five are blue, and two are green. What's the probability of randomly picking

a green or blue marble out of the bag?
A. 0
B. 1/10
C. 1/2
D. 7/10
Mathematics
2 answers:
vlabodo [156]3 years ago
6 0
That answer would be D because 5+2 equals 7
MakcuM [25]3 years ago
4 0
There are 5 blue green marbles and 2 green marbles. Therefore, the probability would be 5 + 2 = 7/10 (D).
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Answer:

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Answer:

D. m∠A=43, m∠B=55, a=20

Step-by-step explanation:

Given:

∆ABC,

m<C = 82°

AB = c = 29

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Required:

m<A, m<C, and a (BC)

SOLUTION:

Find m<B using the law of sines:

\frac{sin(B)}{b} = \frac{sin(C)}{c}

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sin(B)*29 = sin(82)*24

\frac{sin(B)*29}{29} = \frac{sin(82)*24}{29}

sin(B) = \frac{sin(82)*24}{29}

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Find m<A:

m<A = 180 - (82 + 55) => sum of angles in a triangle.

= 180 - 137

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Find a using the law of sines:

\frac{a}{sin(A)} = \frac{b}{sin(B)}

\frac{a}{sin(43)43} = \frac{24}{sin(55)}

Cross multiply

a*sin(55) = 25*sin(43)

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a = 20 (approximated)

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Answer:

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