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kifflom [539]
2 years ago
11

Simplify the expression 4 + 2(6 + 1) +5(5-2)

Mathematics
2 answers:
Ainat [17]2 years ago
8 0

Answer:

a number

Step-by-step explanation:

iVinArrow [24]2 years ago
6 0

Answer:

33

Step-by-step explanation:

4+2(6+1)+5(5-2) = 4+12+2+25-10 = 16+2+15 = 18+15 = 33

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Find the sum of the positive integers less than 200 which are not multiples of 4 and 7​
taurus [48]

Answer:

12942 is the sum of positive integers between 1 (inclusive) and 199 (inclusive) that are not multiples of 4 and not multiples 7.

Step-by-step explanation:

For an arithmetic series with:

  • a_1 as the first term,
  • a_n as the last term, and
  • d as the common difference,

there would be \displaystyle \left(\frac{a_n - a_1}{d} + 1\right) terms, where as the sum would be \displaystyle \frac{1}{2}\, \displaystyle \underbrace{\left(\frac{a_n - a_1}{d} + 1\right)}_\text{number of terms}\, (a_1 + a_n).

Positive integers between 1 (inclusive) and 199 (inclusive) include:

1,\, 2,\, \dots,\, 199.

The common difference of this arithmetic series is 1. There would be (199 - 1) + 1 = 199 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times ((199 - 1) + 1) \times (1 + 199) = 19900 \end{aligned}.

Similarly, positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 4 include:

4,\, 8,\, \dots,\, 196.

The common difference of this arithmetic series is 4. There would be (196 - 4) / 4 + 1 = 49 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 49 \times (4 + 196) = 4900 \end{aligned}

Positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 7 include:

7,\, 14,\, \dots,\, 196.

The common difference of this arithmetic series is 7. There would be (196 - 7) / 7 + 1 = 28 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 28 \times (7 + 196) = 2842 \end{aligned}

Positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 28 (integers that are both multiples of 4 and multiples of 7) include:

28,\, 56,\, \dots,\, 196.

The common difference of this arithmetic series is 28. There would be (196 - 28) / 28 + 1 = 7 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 7 \times (28 + 196) = 784 \end{aligned}.

The requested sum will be equal to:

  • the sum of all integers from 1 to 199,
  • minus the sum of all integer multiples of 4 between 1\! and 199\!, and the sum integer multiples of 7 between 1 and 199,
  • plus the sum of all integer multiples of 28 between 1 and 199- these numbers were subtracted twice in the previous step and should be added back to the sum once.

That is:

19900 - 4900 - 2842 + 784 = 12942.

8 0
3 years ago
I NEED HELP ON THIS PLEASE
Drupady [299]

Answer:

at 12 hours, it's 9 inches.

at 14 hours, it's 14 inches.

at 13 hours it's 16 inches.

I'm not sure if you needed how many inches it snowed an hour, or if you just needed the hours and inches. My apologies.

3 0
3 years ago
PLS ANSWER ASAP <br> simplify (-8^3)^2
Tanya [424]

Answer:

(-8^3)^2

=-8^2*3

=-8^6

=1/8^6

=1/262144

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
What is the domain of the following function: f ( x ) = â x + 2 x â 1 f(x)=x+2x-1 ?
Naya [18.7K]
The domain is -1, 0, 1, 2, 3, 4. Hope this helps.
3 0
3 years ago
CAN ANYONE HELP ME WITH VOLUME OF PRISMS
VladimirAG [237]

Answer:

The formula for the volume of a prism is V=Bh , where B is the base area and h is the height.

Step-by-step explanation:

8 0
3 years ago
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