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Oksi-84 [34.3K]
3 years ago
15

Someone please help me asap!

Mathematics
2 answers:
dezoksy [38]3 years ago
8 0

Answer:

a.) 2x+y

2(4)+3

8+3=11

b.) a^2+b

(-2)^2+5

4+5=9

Step-by-step explanation:

babymother [125]3 years ago
4 0

Answer:

a) 11

b) 9

Step-by-step explanation:

a) x=4  y=3

2x+y

2(4)+(3)

8+3

=11

b) a=-2  b=5

a^2+b

(-2)^2+(5)

4+5

=9

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Which of the following best describes the relationship between (x-2) and the polynomial 2x^3+x^2-3
pantera1 [17]
If (x - 2) is a factor of 2x³ + x² - 3 then for the value of x = 2 the polynominal is equal zero.
Substitute:
2 · 2³ + 2² - 3 = 2 · 8 + 4 - 3 = 16 + 4 - 3 = 17 ≠ 0
Answer: B) (x - 2) is not a factor.

3 0
3 years ago
Please help me solve 7-30 worth 30 points
garri49 [273]

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15. 1.66 16. 2.17 17. 0.0006 18. 0.00034 19. 74% 20. 52% 21. 89% 22. 76.8%


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30. 0.46% Converting Decimal to Percentage, Multiply Decimal by 100. Percentage to Decimal, divide by 100.

8 0
3 years ago
Read 2 more answers
+Brainliest for this one, pts stay 10. Good luck :)
Anon25 [30]

Answer:

7.25 × 10^6

Step-by-step explanation:

1) put into standard form: 6,000,000 + 1,250,000

2) add: 6,000,000 + 1,250,000= 7,250,000

3) put into scientific notation: 7.25 × 10^6

8 0
3 years ago
How do I solve this question?
Sati [7]

Answer:

m=2 and n=3

Step-by-step explanation:

<u>Step</u> :-

Given  [ 2 x^{n}y^{2} ]^m = 4 x^6 y^4

using algebraic formula (a^m)^n= a^{mn}

now

2^{m} x^{mn} y^{2m} = 4x^{6} y^{4}

now equating 'x' powers, we get

x^{mn} = x^{6}

mn=6 ....(1)

now

y^{2m} = y^{4}

Equating 'y' powers ,we get

2 m=4

m=2

substitute m= 2 in equation (1)

we get

2 n=6

n=3

verification:-

substitute m=2 and n=3 , we get

[ 2 x^{n}y^{2} ]^m = 4 x^6 y^4

(2 x^{3} y^2)^2 = 4 x^6 y ^4\\

4 x^6 y^4 = 4 x^6 y^4

both are equating so m= 2 and n=3

4 0
3 years ago
16. Solve the linear equation.<br><br> 12x– 2 = 2x + 18
tino4ka555 [31]

Answer:

x=2

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

6 0
2 years ago
Read 2 more answers
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