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Brut [27]
2 years ago
5

The weight P in pounds that a beam can safely carry is inversely proportional to the distance D in feet between the supports of

the beam. For a certain type of wooden beam, P=7200/D. What distance between supports is needed to carry 2000 lb?
Mathematics
1 answer:
Andrew [12]2 years ago
5 0
I got 5200 I'm not really sure but u can check
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Step-by-step explanation:

f(x)=2x²+3x+9

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In order to find (f⋅g)(1) first find (f⋅g)(x)

To find (f⋅g)(x) substitute g(x) into f(x) , that's for every x in f (x) replace it by g (x)

We have

(f⋅g)(x) = 2( - 3x + 10)² + 3(- 3x + 10) + 9

Expand

(f⋅g)(x) = 2( 9x² - 60x + 100) - 9x + 30 + 9

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Group like terms

(f⋅g)(x) = 18x² - 120x - 9x + 200 + 30 + 9

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To find (f⋅g)(1) substitute 1 into (f⋅g)(x)

That's

(f⋅g)(1) = 18(1)² - 129(1) + 239

= 18 - 129 + 239

We have the final answer as

<h3>(f⋅g)(1) = 128</h3>

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