A) 7.5 % m / V
7.5 g -------- 100 mL ( solution )
mass g ------ 45.0 mL
mass g = 45.0 x 7.5 / 100
mass g = 337.5 / 100 => 3.375 g
1 mole KCl -------------- 74.55 g
moles KCl ---------------- 3.375 g
moles KCl = 3.375 x 1 / 74.55 => 0.0452 moles of KCl
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b) 9.5 % ( m / V ) :
9.5 g -------- 100 mL ( solution )
mass g ------ 400.0 mL
mass g = 400.0 x 9.5 / 100
mass g = 3800 / 100 => 38 g
1 mole acetic acid -------------- 60.05 g
moles acetid acid ---------------- 38 g
moles acetid acid = 38 x 1 / 60.05 => 0.6328 moles of acetid acid<span>
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hope this helps!
Answer: decrease the temperature of the reaction
Explanation:
CH3COOH + CH3CH2OH ⇌ CH3COOCH2CH3 + H2O
The formation of an ester is an exothermic reaction. Therefore, a decrease in the temperature of the reaction will favour the production of ester.
<span>The correct answer should be Oak becaue of the climate. Spruces usually grow in places that are really cold, the more north you go the higher the chance of finding a spruce forest. South of it is usually an Oak forest because the climate is warmer and oaks grow in warmer climates that are not as harsh as those with spruces.</span>
Answer:
There is 18.8% lithium by mass in second sample
Explanation:
Both the two samples are pure lithium carbonate. So % lithium by mass will be same in both samples. This can be proved mathematically as follows-
Let's assume weight of first sample is x g
So, 100 g of sample contains 18.8 g of lithium
Hence, x g of sample contains 
g of lithium
Now, the second sample has weight equal to 2x g
So, 2x g of sample contains 
g of lithium
So, % lithium by mass in second sample = 
% = 18.8%
