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2 years ago

Calculate the atoms of hydrogen in 52.0 g of H2O.

Chemistry

1 answer:

Zarrin [17]2 years ago

5 0

Answer:

34.81 ×10²³ atoms

Explanation:

Given data:

Mass of water = 52.0 g

Number of atoms of hydrogen = ?

Solution:

Number of moles of water:

Number of moles = mass/molar mass

Number of moles = 52.0 g/ 18 g/mol

Number of moles = 2.89 mol

1 mole of water contain 2 mole of hydrogen.

2.89 mole of water contain 2.89× 2= 5.78 moles of hydrogen.

Number of atoms of hydrogen:

1 mole = 6.022×10²³ atoms

5.78 mol × 6.022×10²³ atoms / 1mol

34.81 ×10²³ atoms

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Can someone please answer this?

Amanda [17]

Answer:-

0.229 L

Explanation:-

Molar mass of AgBr = 107.87 x 1 + 79.9 x 1

=187.77 grams mol-1

Mass of AgBr = 150 grams

Number of moles of AgBr = 150 grams / 187.77 gram mol-1

= 0.8 mol

The balanced chemical equation is

NaBr (aq) + AgNO3 (aq)--> AgBr(s) + NaNO3(aq)

From the equation we can see that

1 mol of AgBr is produced from 1 mol of AgNO3.

∴ 0.8 mol of AgBr is produced from 1 x 0.8 / 1 = 0.8 mol of AgNO3.

Strength of AgNO3 = 3.5 M

Volume of AgNO3 required = Number of moles / strength

= 0.8 moles / 3.5

=0.229 L

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3 years ago

Hydrochloric acid and sodium hydroxide are mixed together to form salt and water. During the reaction, the temperature of the so

sammy [17]

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6 0

3 years ago

Given the reaction agi(s) ↔ ag+(aq) + i-(aq) solution equilibrium is reached in the system when

Julli [10]

Missing question:
1) the rate of dissolving reaches zero
<span>2) the rate of crystallization reaches zero </span>
3) the rate of dissolving is zero and the rate of crystallization is greater than zero.
<span>4) both the rate of dissolving and the rate of crystallization are equal and greater than zero.
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3 years ago

What periodic trends exist for electronegativity?

Anna007 [38]

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5 0

3 years ago

What is the empirical formula for a substance that is composed of 40.66% carbon, 8.53% Hydrogen,23.72% Nitrogen, and 27.09% Oxyg

prohojiy [21]

Answer:

THE EMPIRICAL FORMULA OF THE SUBSTANCE IS C2H5NO

Explanation:

The steps involved in calculating the empirical formula of this substance in shown in the table below:

Element Carbon Hydrogen Nitrogen Oxygen

1. % Composition 40.66 8.53 23.72 27.09

2. Mole ratio =

%mass/ atomic mass 40.66/12 8.53/1 23.72/14 27.09/16

= 3.3883 8.53 1,6943 1.6931

3. Divide by smallest

value (0.6931) 3.3883/1.6931 8.53/1.6931 1.6943/1.6931 1.6931/1.6931

= 2.001 5.038 1.0007 1

4. Whole number ratio 2 5 1 1

The empirical formula = C2H5NO

7 0

3 years ago