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Elanso [62]
3 years ago
10

What is the empirical formula of a carbon-oxygen compound, given that a 95.2 g sample of the compound contains 40.8 g of carbon

and the rest oxygen?
Chemistry
1 answer:
algol [13]3 years ago
4 0

Answer:

95.2 - 40.8 = 54.4 g of oxygen

number of moles = mass (g)/ Mr

no. of moles of carbon = 40.8/12 = 3.4

no. of moles of oxygen = 3.4

divide both by smallest value which is 3.4 and you’ll get 1 mole of carbon and 1 mole of oxygen therefore the empirical formula is CO

Explanation:

hope this helps :)

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Hello this is my 3 attempt, please someone answer this i'm begging you.
denis23 [38]

Answer:

Explanation:

No worries, I got you :)

So for the first question, you need to use PV=nRT to find the n, or in other words, the number of moles. Then, you can find the molar mass since you know the grams and the moles

110 kPa / 101.3 = 1.085 atm (I converted it to atm so I can use the .08206 L atm/ k mol  for the rate)

550 ml / 1000 = .550 L (I converted mL to L in order to use the .08206 L atm/ k mol for the Rate)

28.5 c + 273 = 301.5 K (I converted C to K in order to use the .08206 L atm/ k mol for the Rate)

PV=nRT

(1.085) (.550 L) = n (0.08206) (301.5)

Divide the (0.08206) (301.5) to get n alone:

(1.085) (.550 L) / (0.08206) (301.5) = n

When I divided, I got n= .02412 moles, and since we have 1.88g , we divide the 1.88 by .02412 to get the molar mass (grams/mole)

77.94 g/mole is the molar mass

we know that there are 3 H's in the compound, so we do 3(1.008) and subtract 77.94 by what you get.

3 x 1.008 = 3.024 -----> 77.94-3.024 = 74.9

Now we look at the periodic table and try to find an element that has a molar mass of 74.9

Arsenic (As) has a molar mass of 74.922, which is close enough. Plus, Arsenic has a charge of 3, so it fits with the 3 hydrogens.

5 0
3 years ago
A Weather man reports
notsponge [240]

Answer:

???

Explanation:

3 0
3 years ago
An experiment was performed to determine how the amount of coffee grounds could affect the taste of coffee.The same kind of coff
gavmur [86]
What we want to measure is the taste of coffee.

The following were kept constant during the experimental investigation:
The type of coffee,
The type of percolator,
The same amount and type of water,
The same perking time,
The same electrical sources.

Because these items were kept constant, they are not expected to influence the outcome of the experimental investigation.

Define:
y = the metric used to measure the taste of coffee
x = amount of coffee grounds used for the taste experiment.

Therefore the relationship that arises from the experiment is
y = y(x).

Because x is controllable and is varied during the experiment, it is the independent variable.
Because the measured value of y depends on x, therefore y is the dependent variable.

Answer:
The taste of coffee is the dependent variable.
The amount of coffee grounds used is the independent variable.

6 0
3 years ago
On a molar basis, which is a more effective bleaching agent- kbro3 or naocl?
Aleksandr-060686 [28]
<span>On a molar a basis, the most effective bleaching agent kbro3 has more oxygen, but due to the bromine, it would make things look yellowish. The bromine would counteracts the bleaching effect. As we all know, bleach is naocl or hypochlorite</span>
6 0
3 years ago
You want to minimize an objects thermal energy loss on a cold day. How does heat energy transfer affect thermal energy loss?
san4es73 [151]

Answer:

4- A material that transfers heat energy more easily than another material will experience a greater rate of thermal energy loss than an object that does not transfer heat energy easily.

Explanation:

Thermal energy loss has to do with loss of heat energy by a body to another body or its environment. The aim of the process is usually the attainment of thermal equilibrium between the body and its environment.

On a cold day, a material that transfers thermal energy more easily will loose thermal energy faster than an object that does not transfer thermal energy. The rate of heat transfer of a body determines its rate of loss of thermal energy.

6 0
3 years ago
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