Answer:
ΔE = 73 J
Explanation:
By the first law of thermodynamics, the energy in the system must conserved:
ΔE = Q - W
Where ΔE is the internal energy, Q is the heat flow (positive if it's absorbed by the system, and negative if the system loses heat), and W is the work (positive if the system is expanding, and negative if the system is compressing).
So, Q = + 551 J, and W = + 478 J
ΔE = 551 - 478
ΔE = 73 J
The highlighted atoms have sp2 - sp3 hybridization. The highlighted atoms are carbon and nitrogen as shown.
The structure of Xanthine is shown in the image attached to this answer. The indicated atoms are Carbon and nitrogen as shown. Let us remember that hybridization has to do with the mixing of atomic orbitals to form appropriate hybrid orbitals that are suitable for overlap with orbitals of other atoms.
The highlighted carbon atom is sp2 hybridized because it has a carbon nitrogen double bond while the highlighted nitrogen atom is sp3 hybridized. Therefore, the highlighted atoms have sp2 - sp3 hybridization.
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Answer:
E. potassium (K) and bromine (Br)
Explanation:
An ionic bond is formed between compounds with a large electronegativity difference between them. It is usually between a metal and non-metal.
- Potassium is a true metal found in group 1 on the periodic table.
- Bromine is a highly electronegative non-metal which is a halogen.
- Potassium will lose one of its electrons which will be gained by the Bromine.
- The electrostatic attraction between the two species will cause the ionic bond to form.
- The ability of one specie willing to lose electron and the other gaining, is the main bed rock of ionic bonding.
The volume of chlorine gas measured at STP will be liberated by a current of 2.5 A flowing for a period of 1.8 hours through an aqueous solution of AgCl is 1.88 litre.
<h3>What is Faraday's law ?</h3>
According to Faraday's Law , During Electrolysis , The amount of substance liberated at the cathode or anode is directly proportional to the electricity that is passed through the cell.
The reaction taking place at anode is:
2Cl → Cl₂ +2e −
The total charge is calculated as
Q=I×t= 2.5×1.8×60×60 coulomb
Q = 16200 coulomb
The amount of chlorine liberated by passing 16200 coulomb of electric charge
= 16200/(2*96500)
= 0.084 mole
Volume of Cl₂ at STP is
1 mole at STP has 22.4 L of Gas
0.084 mole of Cl₂ at STP will be equal to 22.4 *0.084 = 1.88 litre of Cl₂
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Answer:
The Limiting Reactant is the reactant that when consumed the reaction stops.
Explanation:
