Answer:
This question is incomplete
Explanation:
This question is incomplete but...
1) You can calculate the molarity of the NaOH for each trial by following the steps below.
The formula for Molarity (M) is
M = number of moles (n) ÷ volume (V)
where the unit of volume must be in Litres or dm³
The unit of molarity is mol/dm³ or mol/L or molar conc (M)
The final answer must have the unit of molarity
If the number of moles is not provided, look out for the mass of NaOH used and then calculate your number of moles (n) as
n = mass of NaOH used ÷ molar mass of NaOH
Where the atomic mass of sodium (Na) is 23, oxygen (O) is 16 and hydrogen (H) is 1. Hence, molar mass for NaOH is 23 + 16 + 1 = 40 g/mol
n = mass of NaOH used ÷ 40
2) Average Molarity will be (Trial 1 Molarity +Trial 2 Molarity) ÷ 2
Answer must be in mol/dm³ or mol/L or M
3) Label the volumentric flask containing the NaOH solution with the answer gotten from (2) above
