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miskamm [114]
3 years ago
9

The latent heat of vaporization of water is 540 calories/gram. How many calories are required to completely vaporize 500 grams o

f water? 1,040 cal 40 cal 270,000 cal 1.08 cal
Chemistry
2 answers:
earnstyle [38]3 years ago
8 0

The amount of heat needed to vaporize the given amount of water is the product of the amount in grams and the latent heat of vaporization in cal per gram. That is,

                              H = (540 calories / gram)( 500 grams) = 270,000 cal

Thus, the heat needed is 270, 000 calories. The answer is letter C.

Hope this helps :) thats just a sh

Mars2501 [29]3 years ago
8 0

Answer:

270,000 cal

Explanation:

In order to calculate the calories needed to completely vaporize 500 grams of water we just have to use the formula of the latent heat of vaporization, we know that it takes 540 calories to vaporize a gram of water, so we just multiply that by the number of grams:

(500 grams of water)(540 calories/gram)= 270,000 calories

It would taje 270,000 calories to vaporize 500 grams of water.

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0.895 g/mL

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Step 1: Given data

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Volume of liquid Z (V): 5.93 cups

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2.763 lb \times \frac{453.59 g}{1lb} = 1,253g

Step 3: Convert "V" to milliliters

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