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Veseljchak [2.6K]

2 years ago

6

A box of juice has 5 cups of pineapple juice and 2 cups of orange juice. Write the ratio of cups of pineapple juice to the numbe

r of cups of orange juice. WRITE THE RATIO IN THREE DIFFERENT WAYS. *

1 answer:

Annette [7]2 years ago

7 0

5:2 ,5 to 2 ,5/2 i think that’s right

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3 years ago

An automobile manufacturer obtains the microprocessors used to regulate fuel consumption in its automobiles from three microelec

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Answer:

The probability that a randomly selected automobile manufactured by the company will have a defective microprocessor is 6.2 %.

Step-by-step explanation:

Given:

The probability of getting a microprocessor from firm A is, $P(A)=45\%=0.45$

The probability of getting a microprocessor from firm B is, $P(B)=30\%=0.30$

The probability of getting a microprocessor from firm C is, $P(C)=25\%=0.25$

Now, let event D be having a defective microprocessor at random.

So, as per the question,

Probability of producing a defective microprocessor from firm A is, $P(D/A)=6\%=0.06$

Probability of producing a defective microprocessor from firm B is, $P(D/B)=7\%=0.07$

Probability of producing a defective microprocessor from firm C is, $P(D/C)=5.5\%=0.055$

Now, probability of having a defective microprocessor when selected at random is given as:

$P(D)=P(A)\cdot P(D/A)+P(B)\cdot P(D/B)+P(C)\cdot P(D/C)\\P(D)=(0.45\times 0.06)+(0.30\times 0.07)+(0.25\times 0.055)\\P(D)=0.027+0.021+0.01375\\P(D)=0.06175\ or\ P(D)=0.06175\times 100\approx 6.2\%$

Therefore, the probability that a randomly selected automobile manufactured by the company will have a defective microprocessor is 6.2 %.

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