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Wittaler [7]
3 years ago
15

Find the approximate area of a triangle that has vertices at A(-4,2),B(6,4)C(3,-1)

Mathematics
1 answer:
MrMuchimi3 years ago
6 0

area \: of \: triangle \:  =  \frac{1}{2}  |( - 16) - (22)|
=  \frac{1}{2}  | - 44|
= | - 22|
area \: of \: triangle \:  = 22
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If m< DBG=58 and mDG =74 , find mGE
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Answer:

Option D: mGE = 190°

Step-by-step explanation:

From the property of angles of secant and tangent lines, we have:

DBG = (mGE - mDG)/2

(That is, the angle in point B is half the difference of the larger arc by the smaller arc defined by the lines)

So, we have that:

58 = (mGE - 74)/2

2*58 = mGE - 74

mGE = 116 + 74 = 190°

So we have that mGE is equal to 190°, correct option: D.

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