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3 years ago

Please help me with this question asap

Mathematics

2 answers:

Tju [1.3M]3 years ago

8 0

Answer: 1.25
hope this helps you out .

WITCHER [35]3 years ago

5 0

Answer:

1.25

Step-by-step explanation:

Triangles add up to 180

9x16=144 180/144 = 1.25

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Which ordered pair is a solution of the equation? y=-2x+5y=−2x+5 (Choice A) A Only (2,-9)(2,−9) (Choice B) B Only (-2,9)(−2,9) (

Firdavs [7]

Answer:

Choice B: Only (-2, 9)

Step-by-step explanation:

Of the two choices, only the point (-2, 9) satisfies the equation:

... y = -2x +5

... 9 = -2(-2) +5 = 4 +5 = 9

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4 years ago

Read 2 more answers

ivolga24 [154]

Given:

Two jugs are similar. The smaller jug has radius 4 cm and the bigger jug has radius 6 cm and surface area 125 cm².

To find:

The area of the smaller jug.

Solution:

If two figures are similar, then the ratio of their areas is proportional to the square of the corresponding sides of the figures.

Two jugs are similar. So,

$\dfrac{\text{Area of smaller jug}}{\text{Area of bigger jug}}=\dfrac{(\text{Radius of smaller jug})^2}{(\text{Radius of bigger jug})^2}$

$\dfrac{\text{Area of smaller jug}}{125}=\dfrac{(4)^2}{(6)^2}$

$\dfrac{\text{Area of smaller jug}}{125}=\dfrac{16}{36}$

$\text{Area of smaller jug}=\dfrac{4}{9}\times 125$

$\text{Area of smaller jug}\approx 55.56$

Therefore, the area of the smaller jug is about 55.56 cm².

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3 years ago

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Elena L [17]

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3 years ago

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

Brilliant_brown [7]

Answer:

$f(x)=\sqrt{x-1}$ -----> Graph C

$f(x)=\sqrt{x}$ -----> Graph A

$f(x)=\sqrt{x}-1$ -----> Graph B

$f(x)=-\sqrt{x}$ -----> Graph D

$f(x)=-\sqrt{x-1}$ -----> Graph E

Step-by-step explanation:

we have

case a) $f(x)=\sqrt{x-1}$

Find the domain

we know that

The radicand must be greater than or equal to zero

$x-1\geq 0$

$x\geq 1$

The domain is the interval -----> [1,∞)

All real numbers greater than or equal to 1

The range is the interval -----> [0,∞)

All real numbers greater than or equal to 0

case b) $f(x)=\sqrt{x}$

Find the domain

we know that

The radicand must be greater than or equal to zero

$x\geq 0$

The domain is the interval -----> [0,∞)

All real numbers greater than or equal to 0

The range is the interval -----> [0,∞)

All real numbers greater than or equal to 0

case c) $f(x)=\sqrt{x}-1$

Find the domain

we know that

The radicand must be greater than or equal to zero

$x\geq 0$

The domain is the interval -----> [0,∞)

All real numbers greater than or equal to 0

The range is the interval -----> [-1,∞)

All real numbers greater than or equal to -1

case d) $f(x)=-\sqrt{x}$

Find the domain

we know that

The radicand must be greater than or equal to zero

$x\geq 0$

The domain is the interval -----> [0,∞)

All real numbers greater than or equal to 0

The range is the interval -----> (-∞,0]

All real numbers less than or equal to 0

case e) $f(x)=-\sqrt{x-1}$

Find the domain

we know that

The radicand must be greater than or equal to zero

$x-1\geq 0$

$x\geq 1$

The domain is the interval -----> [1,∞)

All real numbers greater than or equal to 1

The range is the interval -----> (-∞,0]

All real numbers less than or equal to 0

5 0

3 years ago