I need to figure out what the unit to measure time is

Certain compound contains 7.3% carbon, 4.5% hydrogen, 36.4% oxygen, and 31.8% nitrogen. It’s reality molecular mass is 176.0. Fi

erastovalidia [21]

Answer:

The answer to your question is:

Explanation:

Data

carbon 7.3% = 7.3g

hydrogen 4.5% = 4.5g

oxygen 36.4% = 36.4 g

nitrogen 31.8% = 31.8 g

Now

For carbon

12 g --------------------1 mol

7.3 g ------------- x

x = 7.3/12 = 0.608 mol

For hydrogen

1 g -------------------- 1 mol

4.5 g ------------------ x

x = 4.5 mol

For oxygen

16 g ------------------- 1 mol

36.4 g ---------------- x

x = 2.28 mol

For nitrogen

14 g ---------------- 1 mol

31.8 g --------------- x

x = 2.27 mol

Now divide by the lowest result, the is 0.608 from carbon

carbon 0.608/0.608 = 1

hydrogen 4.5/ 0.608 = 7.4

oxygen 2.28/0.608 = 3.75

nitrogen 2.27/0.608 = 3.73

Empirical formula = CH₇O₄N₄

6 0

3 years ago

Which of these could be an adaptive trait to help protect an organism from predators?

saw5 [17]

Answer:

D. Is the correct Option!

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Hope this helps!!! :)

3 0

3 years ago

How many grams of the excess reactant are left over according to the reaction below given that you start with 10.0 g of Al and 1

valentinak56 [21]

4 Al + 3 O2 → 2 Al2O3

(10.0 g Al) / (26.98154 g Al/mol) = 0.37062 mol Al
(19.0 g O2) / (31.99886 g O2/mol) = 0.59377 mol O2

0.37062 mole of Al would react completely with 0.37062 x (3/4) = 0.277965 mole of O2, but there is more O2 present than that, so O2 is in excess.

((0.59377 mol O2 initially) - (0.277965 mol O2 reacted)) x (31.99886 g O2/mol) =
10.1 g O2 left over

7 0

4 years ago

Read 2 more answers

One gram of alum, KAl(SO4)2.12H2O, contains 1.3 × 1021 Al atoms. How many oxygen atoms are contained in 1.0 g alum?

Roman55 [17]

From the chemical formula, 1 formula unit of KAl (SO4)2.12H2O encompasses 1 atom of Al = 4 * 2 atoms of O in KAl (SO4)2 + 12 atoms of O in 12H2O which is equal to 20 atoms of O.

So, if you have 1.3 × 10^21 Al atoms, you have 20 * 1.3 × 10^21 O atoms will now be equal to 2.6 * 10^22 atoms of O.

6 0

3 years ago

Read 2 more answers

If the mass of the baking soda before the reaction was 10 grams and the mass of the vinegar was 15 grams and all of the baking s

Masteriza [31]

Answer:

8.946g NaHCO₃,

14.475g H₂O,

1.025g CH₃COO⁻Na⁺,

0.500g CO₂.

Explanation:

Baking soda (NaHCO₃) reacts with vinegar (CH₃COOH 5%) producing CH₃COO⁻Na⁺, H₂O and CO₂, thus:

NaHCO₃ + CH₃COOH → CH₃COO⁻Na⁺ + H₂O + CO₂

10g of NaHCO₃ are:

10g × (1mol / 84g) = 0.119 moles NaHCO₃

Moles of CH₃COOH in 15g of vinegar are:

15g vinegar × 5% = 0.75g CH₃COOH × (1mol / 60g) = 0.0125moles CH₃ COOH

After reaction, moles of NaHCO₃ that remains are:

0.119mol - 0.0125mol = 0.1065 moles NaHCO₃

In mass:

0.1065mol ₓ (84g / 1mol) = 8.946g NaHCO₃

Acetic acid reacts completely producing 0.0125moles of CH₃COO⁻Na⁺, water and CO₂. In mass:

CH₃COO⁻Na⁺ = 0.0125mol ₓ (82.03g / 1mol) = 1.025g CH₃COO⁻Na⁺

H₂O = 0.0125mol ₓ (18.01g / 1mol) = 0.225g H₂O

CO₂ = 0.0125mol ₓ (40g / 1mol) = 0.500g CO₂

Now, 95% of vinegar is water (Doesn't react), that is:

15g × 95% = 14.25g H₂O. Total mass of water is:

14.25g + 0.225g = 14.475g H₂O

Total mass is:

8.946g + 14.475g H₂O + 1.025g + 0.500g ≈ 25g. The same than initial mass following law of conservation of matter.

6 0

3 years ago